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 Solution Find In ratio and proportion, if (5a+6b)/(7c)=(6b+7c)/(5a)=(7c+5a)/(6b) then prove that each ratio = 2,-1Solution:Your problem -> In ratio and proportion, if (5a+6b)/(7c)=(6b+7c)/(5a)=(7c+5a)/(6b) then prove that each ratio = 2,-1Here (5a+6b)/(7c)=(6b+7c)/(5a)=(7c+5a)/(6b)Case-1 : If 5a+6b+7c!=0, then Each ratio=(5a+6b+6b+7c+7c+5a)/(7c+5a+6b)=(10a+12b+14c)/(7c+5a+6b)=(2(5a+6b+7c))/(7c+5a+6b)Cancel the common factor (5a+6b+7c)=2Case-2 : If 5a+6b+7c=0, then 5a+6b=-7cThen, the first ratio =(5a+6b)/(7c)=(-7c)/(7c)Cancel the common factor 7c=-1Hence, each ratio =-1.Thus, the value of each ratio is 2 or -1. Solution provided by AtoZmath.com Any wrong solution, solution improvement, feedback then Submit Here Want to know about AtoZmath.com and me