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Find Inverse matrix 7y+2x=11,3x-y=5

Solution:
Your problem `->` Inverse matrix 7y+2x=11,3x-y=5


Here `7y+2x=11`
` 3x-y=5`

Now converting given equations into matrix form
`[[2,7],[3,-1]] [[x],[y]]=[[11],[5]]`

Now, A = `[[2,7],[3,-1]]`, X = `[[x],[y]]` and B = `[[11],[5]]`

`:. AX = B`

`:. X = A^-1 B`

`|A|` = 
 `2`  `7` 
 `3`  `-1` 


`=2 × (-1) - 7 × 3`

`=-2 -21`

`=-23`


`"Here, " |A| = -23 != 0`

`:. A^(-1) " is possible."`






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