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Solution will be displayed step by step (In 2 parts)
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Solution
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Problem: Matrix method of Game Theory {{1,7,2},{6,2,7},{5,1,6}} [ Calculator, Method and examples ]
Solution: Your problem `->` Matrix method of Game Theory {{1,7,2},{6,2,7},{5,1,6}}
1. Saddle point testing Players
| | | Player `B` | | | | | | `B_1` | `B_2` | `B_3` | | | Player `A` | `A_1` | | 1 | 7 | 2 | | | `A_2` | | 6 | 2 | 7 | | | `A_3` | | 5 | 1 | 6 | | |
We apply the maximin (minimax) principle to analyze the game.
| | | Player `B` | | | | | | `B_1` | `B_2` | `B_3` | | Row Minimum | Player `A` | `A_1` | | 1 | 7 | 2 | | `1` | `A_2` | | (6) | [2] | 7 | | `[2]` | `A_3` | | 5 | 1 | 6 | | `1` | | Column Maximum | | `(6)` | `7` | `7` | | |
Select minimum from the maximum of columns Column MiniMax = (6)
Select maximum from the minimum of rows Row MaxiMin = [2]
Here, Column MiniMax `!=` Row MaxiMin
`:.` This game has no saddle point.
2. Dominance rule to reduce the size of the payoff matrix Using dominance property
| | | Player `B` | | | | | | `B_1` | `B_2` | `B_3` | | | Player `A` | `A_1` | | 1 | 7 | 2 | | | `A_2` | | 6 | 2 | 7 | | | `A_3` | | 5 | 1 | 6 | | |
row-3 is dominated by row-2 (row-3 `<=` row-2), so row-3 is deleted, `(A_3 <= A_2 : 5<=6,1<=2,6<=7)`
| | | Player `B` | | | | | | `B_1` | `B_2` | `B_3` | | | Player `A` | `A_1` | | 1 | 7 | 2 | | | `A_2` | | 6 | 2 | 7 | | |
column-3 is dominated by column-1 (column-3 `>=` column-1), so column-3 is deleted. `(B_3 >= B_1 : 2>=1,7>=6)`
| | | Player `B` | | | | | | `B_1` | `B_2` | | | Player `A` | `A_1` | | 1 | 7 | | | `A_2` | | 6 | 2 | | |
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