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Find Regression line {{10,3},{11,12},{12,18},{13,12},{14,3}} [ Calculator, Method and examples ]

Solution:
Your problem `->` Regression line {{10,3},{11,12},{12,18},{13,12},{14,3}}


Mean `bar x = (sum x_i)/n`

` = (10+11+12+13+14)/5`

` = 60/5`

` = 12`

Mean `bar y = (sum y_i)/n`

` = (3+12+18+12+3)/5`

` = 48/5`

` = 9.6`

`bar x = 12` is not an integer, use assumed mean `A = 12`

`bar y = 9.6` is not an integer, use assumed mean `B = 10`

`x``y``dx=x-A=x-12``dy=y-B=y-10``dx^2``dy^2``dx*dy`
103 -2 `-2=10-12` -7 `-7=3-10` 4 `4=(-2)^2` 49 `49=(-7)^2` 14 `14=-2 xx -7`
1112 -1 `-1=11-12` 2 `2=12-10` 1 `1=(-1)^2` 4 `4=(2)^2` -2 `-2=-1 xx 2`
1218 0 `0=12-12` 8 `8=18-10` 0 `0=(0)^2` 64 `64=(8)^2` 0 `0=0 xx 8`
1312 1 `1=13-12` 2 `2=12-10` 1 `1=(1)^2` 4 `4=(2)^2` 2 `2=1 xx 2`
143 2 `2=14-12` -7 `-7=3-10` 4 `4=(2)^2` 49 `49=(-7)^2` -14 `-14=2 xx -7`
---------------------
`60``48``sum dx=0``sum dy=-2``sum dx^2=10``sum dy^2=170``sum dx*dy=0`


`byx = (n sum dx dy - (sum dx)(sum dy))/(n sum dx^2 - (sum dx)^2)`

`=(5 * 0 - 0 * -2 )/(5 * 10 - (0)^2)`

`=(0 + 0 )/(50 - 0)`

`=0/50`

`=0`


Regression Line y on x





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