Home > Geometry calculators > Coordinate Geometry > Find the area of a triangle whose vertices are A(4,1),B(-2,-3),C(6,7)

Solve any problem
(step by step solutions)
Input table (Matrix, Statistics)
Mode :
SolutionHelp
Solution
Find area of a triangle whose vertices are A(4,1),B(-2,-3),C(6,7)

Solution:
Your problem `->` area of a triangle whose vertices are A(4,1),B(-2,-3),C(6,7)


Here `A(4,1), B(-2,-3), C(6,7)` are the given points

`:. x_1=4, y_1=1, x_2=-2, y_2=-3, x_3=6, y_3=7`

Area of a triangle
`=1/2 |[x_1,y_1,1],[x_2,y_2,1],[x_2,y_2,1]|`

`=1/2 |[4,1,1],[-2,-3,1],[6,7,1]|`

`=1/2[4 (-3 × 1 - 1 × 7) - 1 (-2 × 1 - 1 × 6) + 1 (-2 × 7 - -3 × 6)]`

`=1/2[4 (-3 - 7) - 1 (-2 - 6) + 1 (-14 - -18)]`

`=1/2[4 (-10) - 1 (-8) + 1 (4)]`

`=1/2[-40 + 8 + 4]`

`=1/2[-28]`

`=-14`

`=14` (As area is positive)







Solution provided by AtoZmath.com
Any wrong solution, solution improvement, feedback then Submit Here
Want to know about AtoZmath.com and me
  
 

Share with your friends
 
Copyright © 2018. All rights reserved. Terms, Privacy