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 Solution Find area of a triangle whose vertices are A(4,1),B(-2,-3),C(6,7)Solution:Your problem -> area of a triangle whose vertices are A(4,1),B(-2,-3),C(6,7)Here A(4,1), B(-2,-3), C(6,7) are the given points:. x_1=4, y_1=1, x_2=-2, y_2=-3, x_3=6, y_3=7Area of a triangle=1/2 |[x_1,y_1,1],[x_2,y_2,1],[x_2,y_2,1]|=1/2 |[4,1,1],[-2,-3,1],[6,7,1]|=1/2[4 (-3 × 1 - 1 × 7) - 1 (-2 × 1 - 1 × 6) + 1 (-2 × 7 - -3 × 6)]=1/2[4 (-3 - 7) - 1 (-2 - 6) + 1 (-14 - -18)]=1/2[4 (-10) - 1 (-8) + 1 (4)]=1/2[-40 + 8 + 4]=1/2[-28]=-14=14 (As area is positive) Solution provided by AtoZmath.com Any wrong solution, solution improvement, feedback then Submit Here Want to know about AtoZmath.com and me