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Solution:
Your problem -> hexadecimal BAC/AB

Solution is
 1 1 AB B A C − A B = AB × 1 F C − A B = AB × 1 5 1

:. BAC -: AB = 11 Remainder 51
 AB table AB × 1 = AB AB × 2 = 156 AB × 3 = 201 AB × 4 = 2AC AB × 5 = 357 AB × 6 = 402 AB × 7 = 4AD AB × 8 = 558 AB × 9 = 603 AB × A = 6AE AB × B = 759 AB × C = 804 AB × D = 8AF AB × E = 95A AB × F = A05 AB × 10 = AB0

Step by step solution :
Step-1 :
Set up the problem with long division bracket. Put dividend inside bracket and divisor on outside left.
 AB B A C

Step-2 :
AB goes into BA (1-times). Put a 1 in the next place of quotient and multiply AB by 1 to get AB.
Subtract AB from BA to get remainder (BA-AB=F).

 1 AB B A C − A B = AB × 1 F

Step-3 :
Now, bring down C from the dividend, to make FC
 1 AB B A C − A B = AB × 1 F C

Step-4 :
AB goes into FC (1-times). Put a 1 in the next place of quotient and multiply AB by 1 to get AB.
Subtract AB from FC to get remainder (FC-AB=51).

 1 1 AB B A C − A B = AB × 1 F C − A B = AB × 1 5 1

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