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Find hexadecimal BAC/AB

Solution:
Your problem `->` hexadecimal BAC/AB


Solution is
  11
ABBAC
AB  = AB × 1
  FC
 AB = AB × 1
  51

`:.` BAC `-:` AB = 11 Remainder 51
AB table
AB×1=AB
AB×2=156
AB×3=201
AB×4=2AC
AB×5=357
AB×6=402
AB×7=4AD
AB×8=558
AB×9=603
AB×A=6AE
AB×B=759
AB×C=804
AB×D=8AF
AB×E=95A
AB×F=A05
AB×10=AB0




Step by step solution :
Step-1 :
Set up the problem with long division bracket. Put dividend inside bracket and divisor on outside left.
    
ABBAC

Step-2 :
AB goes into BA (1-times). Put a 1 in the next place of quotient and multiply AB by 1 to get AB.
Subtract AB from BA to get remainder `(BA-AB=F)`.


  1 
ABBAC
AB  = AB × 1
  F 

Step-3 :
Now, bring down C from the dividend, to make FC
  1 
ABBAC
AB  = AB × 1
  FC

Step-4 :
AB goes into FC (1-times). Put a 1 in the next place of quotient and multiply AB by 1 to get AB.
Subtract AB from FC to get remainder `(FC-AB=51)`.


  11
ABBAC
AB  = AB × 1
  FC
 AB = AB × 1
  51






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