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Problem: hexadecimal BAC/AB [ Calculator, Method and examples ]

Solution:
Your problem -> hexadecimal BAC/AB

Solution is
 1 1 .7 9 4 3 AB B A C .0 0 0 0 − A B = AB × 1 F C − A B = AB × 1 5 1 0 − 4 A D = AB × 7 6 3 0 − 6 0 3 = AB × 9 2 D 0 − 2 A C = AB × 4 2 4 0 − 2 0 1 = AB × 3 3 F

:. BAC -: AB = 11.7943...
 AB table AB × 1 = AB AB × 2 = 156 AB × 3 = 201 AB × 4 = 2AC AB × 5 = 357 AB × 6 = 402 AB × 7 = 4AD AB × 8 = 558 AB × 9 = 603 AB × A = 6AE AB × B = 759 AB × C = 804 AB × D = 8AF AB × E = 95A AB × F = A05 AB × 10 = AB0

Step by step solution :
Step-1 :
Set up the problem with long division bracket. Put dividend inside bracket and divisor on outside left.
 AB B A C

Step-2 :
AB goes into BA (1-times). Put a 1 in the next place of quotient and multiply AB by 1 to get AB.
Subtract AB from BA to get remainder (BA-AB=F).

 1 AB B A C − A B = AB × 1 F

Step-3 :
Now, bring down C from the dividend, to make FC
 1 AB B A C − A B = AB × 1 F C

Step-4 :
AB goes into FC (1-times). Put a 1 in the next place of quotient and multiply AB by 1 to get AB.
Subtract AB from FC to get remainder (FC-AB=51).

 1 1 AB B A C − A B = AB × 1 F C − A B = AB × 1 5 1

Step-5 :
Now, bring down 0 from the dividend, to make 510
 1 1 AB B A C .0 − A B = AB × 1 F C − A B = AB × 1 5 1 0

Step-6 :
AB goes into 510 (7-times). Put a 7 in the next place of quotient and multiply AB by 7 to get 4AD.
Subtract 4AD from 510 to get remainder (510-4AD=63).

 1 1 7 AB B A C .0 − A B = AB × 1 F C − A B = AB × 1 5 1 0 − 4 A D = AB × 7 6 3

Step-7 :
Now, bring down 0 from the dividend, to make 630
 1 1 7 AB B A C .0 0 − A B = AB × 1 F C − A B = AB × 1 5 1 0 − 4 A D = AB × 7 6 3 0

Step-8 :
AB goes into 630 (9-times). Put a 9 in the next place of quotient and multiply AB by 9 to get 603.
Subtract 603 from 630 to get remainder (630-603=2D).

 1 1 7 9 AB B A C .0 0 − A B = AB × 1 F C − A B = AB × 1 5 1 0 − 4 A D = AB × 7 6 3 0 − 6 0 3 = AB × 9 2 D

Step-9 :
Now, bring down 0 from the dividend, to make 2D0
 1 1 7 9 AB B A C .0 0 0 − A B = AB × 1 F C − A B = AB × 1 5 1 0 − 4 A D = AB × 7 6 3 0 − 6 0 3 = AB × 9 2 D 0

Step-10 :
AB goes into 2D0 (4-times). Put a 4 in the next place of quotient and multiply AB by 4 to get 2AC.
Subtract 2AC from 2D0 to get remainder (2D0-2AC=24).

 1 1 7 9 4 AB B A C .0 0 0 − A B = AB × 1 F C − A B = AB × 1 5 1 0 − 4 A D = AB × 7 6 3 0 − 6 0 3 = AB × 9 2 D 0 − 2 A C = AB × 4 2 4

Step-11 :
Now, bring down 0 from the dividend, to make 240
 1 1 7 9 4 AB B A C .0 0 0 0 − A B = AB × 1 F C − A B = AB × 1 5 1 0 − 4 A D = AB × 7 6 3 0 − 6 0 3 = AB × 9 2 D 0 − 2 A C = AB × 4 2 4 0

Step-12 :
AB goes into 240 (3-times). Put a 3 in the next place of quotient and multiply AB by 3 to get 201.
Subtract 201 from 240 to get remainder (240-201=3F).

 1 1 7 9 4 3 AB B A C .0 0 0 0 − A B = AB × 1 F C − A B = AB × 1 5 1 0 − 4 A D = AB × 7 6 3 0 − 6 0 3 = AB × 9 2 D 0 − 2 A C = AB × 4 2 4 0 − 2 0 1 = AB × 3 3 F

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