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Problem: hexadecimal BAC/AB [ Calculator, Method and examples ]

Solution:
Your problem `->` hexadecimal BAC/AB


Solution is
  11.7943
ABBAC.0000
AB      = AB × 1
  FC    
 AB     = AB × 1
  510   
 4AD    = AB × 7
  630  
  603   = AB × 9
  2D0 
  2AC  = AB × 4
  240
  201 = AB × 3
  3F

`:.` BAC `-:` AB = 11.7943...
AB table
AB×1=AB
AB×2=156
AB×3=201
AB×4=2AC
AB×5=357
AB×6=402
AB×7=4AD
AB×8=558
AB×9=603
AB×A=6AE
AB×B=759
AB×C=804
AB×D=8AF
AB×E=95A
AB×F=A05
AB×10=AB0




Step by step solution :
Step-1 :
Set up the problem with long division bracket. Put dividend inside bracket and divisor on outside left.
    
ABBAC

Step-2 :
AB goes into BA (1-times). Put a 1 in the next place of quotient and multiply AB by 1 to get AB.
Subtract AB from BA to get remainder `(BA-AB=F)`.


  1 
ABBAC
AB  = AB × 1
  F 

Step-3 :
Now, bring down C from the dividend, to make FC
  1 
ABBAC
AB  = AB × 1
  FC

Step-4 :
AB goes into FC (1-times). Put a 1 in the next place of quotient and multiply AB by 1 to get AB.
Subtract AB from FC to get remainder `(FC-AB=51)`.


  11
ABBAC
AB  = AB × 1
  FC
 AB = AB × 1
  51

Step-5 :
Now, bring down 0 from the dividend, to make 510
  11 
ABBAC.0
AB   = AB × 1
  FC 
 AB  = AB × 1
  510

Step-6 :
AB goes into 510 (7-times). Put a 7 in the next place of quotient and multiply AB by 7 to get 4AD.
Subtract 4AD from 510 to get remainder `(510-4AD=63)`.


  117
ABBAC.0
AB   = AB × 1
  FC 
 AB  = AB × 1
  510
 4AD = AB × 7
  63

Step-7 :
Now, bring down 0 from the dividend, to make 630
  117 
ABBAC.00
AB    = AB × 1
  FC  
 AB   = AB × 1
  510 
 4AD  = AB × 7
  630

Step-8 :
AB goes into 630 (9-times). Put a 9 in the next place of quotient and multiply AB by 9 to get 603.
Subtract 603 from 630 to get remainder `(630-603=2D)`.


  1179
ABBAC.00
AB    = AB × 1
  FC  
 AB   = AB × 1
  510 
 4AD  = AB × 7
  630
  603 = AB × 9
  2D

Step-9 :
Now, bring down 0 from the dividend, to make 2D0
  1179 
ABBAC.000
AB     = AB × 1
  FC   
 AB    = AB × 1
  510  
 4AD   = AB × 7
  630 
  603  = AB × 9
  2D0

Step-10 :
AB goes into 2D0 (4-times). Put a 4 in the next place of quotient and multiply AB by 4 to get 2AC.
Subtract 2AC from 2D0 to get remainder `(2D0-2AC=24)`.


  11794
ABBAC.000
AB     = AB × 1
  FC   
 AB    = AB × 1
  510  
 4AD   = AB × 7
  630 
  603  = AB × 9
  2D0
  2AC = AB × 4
  24

Step-11 :
Now, bring down 0 from the dividend, to make 240
  11794 
ABBAC.0000
AB      = AB × 1
  FC    
 AB     = AB × 1
  510   
 4AD    = AB × 7
  630  
  603   = AB × 9
  2D0 
  2AC  = AB × 4
  240

Step-12 :
AB goes into 240 (3-times). Put a 3 in the next place of quotient and multiply AB by 3 to get 201.
Subtract 201 from 240 to get remainder `(240-201=3F)`.


  117943
ABBAC.0000
AB      = AB × 1
  FC    
 AB     = AB × 1
  510   
 4AD    = AB × 7
  630  
  603   = AB × 9
  2D0 
  2AC  = AB × 4
  240
  201 = AB × 3
  3F








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