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Find interquartile range {1,2,3,2,3,6}

Solution:
Your problem `->` interquartile range {1,2,3,2,3,6}


Arranging Observations in the ascending order, We get :
`1, 2, 2, 3, 3, 6`

Here, `n = 6`

`Q_1 = ((n+1)/4)^(th)` value of the observation

`=(7/4)^(th)` value of the observation

`=(1.75)^(th)` value of the observation

`=1^(st)` observation ` + 0.75 [2^(nd) - 1^(st)]`

`=1 + 0.75 [2 - 1]`

`=1 + 0.75 (1)`

`=1 + 0.75`

`=1.75`



`Q_3 = ((3(n+1))/4)^(th)` value of the observation

`=((3*7)/4)^(th)` value of the observation

`=(5.25)^(th)` value of the observation

`=5^(th)` observation ` + 0.25 [6^(th) - 5^(th)]`

`=3 + 0.25 [6 - 3]`

`=3 + 0.25 (3)`

`=3 + 0.75`

`=3.75`



interquartile range `=Q_3 - Q_1=3.75-1.75=2`






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