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 Find iteration method 2x^3-2x-5, a=1, b=4 [ Calculator, Method and examples ]Solution:Your problem -> iteration method 2x^3-2x-5, a=1, b=4Method-1Let f(x) = 2x^3-2x-5Here 2x^3-2x-5=0:.2x^3-2x=5:.2x(x^2-1)=5:.2x=(5)/(x^2-1):.x=((5)/(x^2-1))/2:.phi(x)=((5)/(x^2-1))/2Here f(1) = -5 < 0 and f(4) = 115 > 0:. Root lies between 1 and 4x_0 = (1 + 4)/2 = 2.5x_1 = phi(x_0) = phi(2.5) = 0.4762x_2 = phi(x_1) = phi(0.4762) = -3.2331x_3 = phi(x_2) = phi(-3.2331) = 0.2645x_4 = phi(x_3) = phi(0.2645) = -2.688

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