Home > Geometry calculators > Coordinate Geometry > Find the equation of a line passing through point A(5,5) and perpendicular to the line 2x+3y+4=0

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 Solution Find line through (5,5) and perpendicular to 2x+3y+4=0Solution:Your problem -> line through (5,5) and perpendicular to 2x+3y+4=0When two lines are perpendicular, their slopes are opposite reciprocals of one another or the product of their slopes is -1.We shall first find the slope of line 2x+3y+4=02x+3y+4=0:. 3y=-2x-4:. y=-(2x)/(3)-4/3:. Slope=-2/3:. Slope of perpendicular line=3/2The equation of a line with slope m and passing through (x_1,y_1) is y-y_1=m(x-x_1)Putting (5,5) for (x_1,y_1) and m=3/2, we get:. y-5=3/2(x-5):. 2(y-5)=3(x-5):. 2y -10=3x -15:. 3x-2y-5=0 Solution provided by AtoZmath.com Any wrong solution, solution improvement, feedback then Submit Here Want to know about AtoZmath.com and me