Home > Geometry calculators > Coordinate Geometry > Find the equation of a line passing through point A(5,5) and perpendicular to the line 2x+3y+4=0

Solve any problem
(step by step solutions)
Input table (Matrix, Statistics)
Mode :
Find line through (5,5) and perpendicular to 2x+3y+4=0

Your problem `->` line through (5,5) and perpendicular to 2x+3y+4=0

When two lines are perpendicular, their slopes are opposite reciprocals of one another or the product of their slopes is -1.
We shall first find the slope of line `2x+3y+4=0`


`:. 3y=-2x-4`

`:. y=-(2x)/(3)-4/3`

`:.` Slope`=-2/3`

`:.` Slope of perpendicular line`=3/2`

The equation of a line with slope m and passing through `(x_1,y_1)` is `y-y_1=m(x-x_1)`

Putting `(5,5)` for `(x_1,y_1)` and `m=3/2,` we get

`:. y-5=3/2(x-5)`

`:. 2(y-5)=3(x-5)`

`:. 2y -10=3x -15`

`:. 3x-2y-5=0`

Solution provided by AtoZmath.com
Any wrong solution, solution improvement, feedback then Submit Here
Want to know about AtoZmath.com and me

Share with your friends, if solutions are helpful to you.
Copyright © 2019. All rights reserved. Terms, Privacy