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Solution
Find mean deviation about mean {{10,11,12,13,14},{3,12,18,12,3}}

Solution:
Your problem `->` mean deviation about mean {{10,11,12,13,14},{3,12,18,12,3}}


`x`
`(1)`
`f`
`(2)`
`f*x`
`(3)=(2)xx(1)`
`|x-bar x|=|x-12|`
`(4)`
`f*|x-bar x|`
`(5)=(2)xx(4)`
103 30 `30=3xx10`
`(3)=(2)xx(1)`
 2 `|x - 12|=|10-12|=2` 6 `6=3xx2`
`(5)=(2)xx(4)`
1112 132 `132=12xx11`
`(3)=(2)xx(1)`
 1 `|x - 12|=|11-12|=1` 12 `12=12xx1`
`(5)=(2)xx(4)`
1218 216 `216=18xx12`
`(3)=(2)xx(1)`
 0 `|x - 12|=|12-12|=0` 0 `0=18xx0`
`(5)=(2)xx(4)`
1312 156 `156=12xx13`
`(3)=(2)xx(1)`
 1 `|x - 12|=|13-12|=1` 12 `12=12xx1`
`(5)=(2)xx(4)`
143 42 `42=3xx14`
`(3)=(2)xx(1)`
 2 `|x - 12|=|14-12|=2` 6 `6=3xx2`
`(5)=(2)xx(4)`
---------------
--`n=48``sum f*x=576`--`sum f*|x-bar x|=36`


Mean `bar x=(sum f x)/n`

`=576/48`

`=12`

Mean deviation of Mean
`delta bar x = (sum f*|x - bar x|)/n`






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