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Problem: median {{10-20,15},{20-30,25},{30-40,20},{40-50,12},{50-60,8}} [ Calculator, Method and examples ]

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Your problem -> median {{10-20,15},{20-30,25},{30-40,20},{40-50,12},{50-60,8}}

 Class(1) Frequency (f)(2) cf(7) 10 - 20 15 15 20 - 30 25 40 30 - 40 20 60 40 - 50 12 72 50 - 60 8 80 --- --- --- n = 80 -----

To find Median Class
= value of (n/2)^(th) observation

= value of (80/2)^(th) observation

= value of 40^(th) observation

From the column of cumulative frequency cf, we find that the 40^(th) observation lies in the class 30 - 40.

:. The median class is 30 - 40.

Now,
:. L = lower boundary point of median class =30

:. n = Total frequency =80

:. cf = Cumulative frequency of the class preceding the median class =40

:. f = Frequency of the median class =20

:. c = class length of median class =10

Median M = L + (n/2 - cf)/f * c

=30 + (40 - 40)/20 * 10

=30 + (0)/20 * 10

=30 + 0

=30

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