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Problem: mode {{10-20,20-30,30-40,40-50,50-60},{15,25,20,12,8}} [ Calculator, Method and examples ]

Solution:
Your problem `->` mode {{10-20,20-30,30-40,40-50,50-60},{15,25,20,12,8}}


Class
`(1)`
Frequency `(f)`
`(2)`
10 - 2015
20 - 3025
30 - 4020
40 - 5012
50 - 608
------
`n = 80`


To find Mode Class
Here, maximum frequency is `25`.

`:.` The mode class is `20 - 30`.

`:. L = `lower boundary point of mode class `=20`

`:. f_1 = ` frequency of the mode class `=25`

`:. f_0 = ` frequency of the preceding class `=15`

`:. f_2 = ` frequency of the succedding class `=20`

`:. c = ` class length of mode class `=10`

`Z = L + ((f_1 - f_0) / (2*f_1 - f_0 - f_2)) * c`

`=20 + ((25 - 15)/(2*25 - 15 - 20)) * 10`

`=20 + (10/15) * 10`

`=20 + 6.6667`

`=26.6667`








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