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Find muller method 2x^3-2x-5, a=0, b=1, c=2

Your problem `->` muller method 2x^3-2x-5, a=0, b=1, c=2

Here `2x^3-2x-5=0`

Let `f(x) = 2x^3-2x-5`

`x_0 = 0`

`x_1 = 1`

`x_2 = 2`

`1^(st)` iteration :









`b=a xx h_2 + d_2=6xx1+12=18`


`x_3=x_2+(-2c)/(b +- sqrt(b^2-4ac))`

`x_3=x_2+(-2c)/(b +sign(b) sqrt(b^2-4ac))`

`=2+(-2 xx 7)/(18 + sqrt(18^2 - 4xx 6 xx 7))`

`=2+(-14)/(18 + sqrt(156))`

`=2+(-14)/(18 + 12.49)`


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