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Find newton raphson method 2x^3-2x-5, a=1, b=4

Solution:
Your problem `->` newton raphson method 2x^3-2x-5, a=1, b=4


Here `2x^3-2x-5=0`

Let `f(x) = 2x^3-2x-5`

`:. f'(x) = 6x^(2)-2`


Here `f(1) = -5 < 0 and f(4) = 115 > 0`

`:.` Root lies between `1` and `4`

`x_0 = (1 + 4)/2 = 2.5`

`x_0 = 2.5`


`1^(st)` iteration :

`f(x_0)=f(2.5)=2*2.5^(3)-2*2.5-5=21.25`






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