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 Find newton raphson method 2x^3-2x-5, a=1, b=4 [ Calculator, Method and examples ]Solution:Your problem -> newton raphson method 2x^3-2x-5, a=1, b=4Here 2x^3-2x-5=0Let f(x) = 2x^3-2x-5:. f'(x) = 6x^(2)-2Here f(1) = -5 < 0 and f(4) = 115 > 0:. Root lies between 1 and 4x_0 = (1 + 4)/2 = 2.5x_0 = 2.51^(st) iteration :f(x_0)=f(2.5)=2(2.5)^(3)-2(2.5)-5=21.25f'(x_0)=f'(2.5)=6(2.5)^(2)-2=35.5

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