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 Solution Find right angle triangle A(0,0),B(0,3),C(4,0)Solution:Your problem -> right angle triangle A(0,0),B(0,3),C(4,0)Here A(0,0), B(0,3), C(4,0) are the given pointsAB^2 = (0-0)^2 + (3-0)^2 = (0)^2 + (3)^2 = 0 + 9 = 9BC^2 = (4-0)^2 + (0-3)^2 = (4)^2 + (-3)^2 = 16 + 9 = 25AC^2 = (4-0)^2 + (0-0)^2 = (4)^2 + (0)^2 = 16 + 0 = 16:. AB^2+AC^2=9+16=25=BC^2:. /_A=90^circ:. ABC is an right angle triangle Solution provided by AtoZmath.com Any wrong solution, solution improvement, feedback then Submit Here Want to know about AtoZmath.com and me