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Find right angle triangle A(0,0),B(0,3),C(4,0)

Solution:
Your problem `->` right angle triangle A(0,0),B(0,3),C(4,0)


Here `A(0,0), B(0,3), C(4,0)` are the given points

`AB^2 = (0-0)^2 + (3-0)^2 = (0)^2 + (3)^2 = 0 + 9 = 9`

`BC^2 = (4-0)^2 + (0-3)^2 = (4)^2 + (-3)^2 = 16 + 9 = 25`

`AC^2 = (4-0)^2 + (0-0)^2 = (4)^2 + (0)^2 = 16 + 0 = 16`

`:. AB^2+AC^2=9+16=25=BC^2`

`:. /_A=90^circ`

`:.` ABC is an right angle triangle








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