1. `y=x^2+3x-4`, find Intercept of a function
Solution:
`y=x^2+3x-4`
1. Intercepts :
Intercept :
To find the y-intercept put x=0 in `y=x^2+3x-4`, we get
`y=(0)^2+3(0)-4=-4`
`:.` y-intercept is `(0,-4)`
To find the x-intercept put y=0 in `y=x^2+3x-4`, we get
`=>x^2+3x-4=0`
`=>x^2-x+4x-4 = 0`
`=>x(x-1)+4(x-1) = 0`
`=>(x-1)(x+4) = 0`
`=>(x-1) = 0" or "(x+4) = 0`
`=>x = 1" or "x = -4`
`:.` x-intercepts are `(1,0)` and `(-4,0)`
This material is intended as a summary. Use your textbook for detail explanation.
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