Step by step solution :Step-1 :Set up the problem with long division bracket. Put dividend inside bracket and divisor on outside left.
Step-2 :19 goes into 71 (3-times). Put a 3 in the next place of quotient and multiply 19 by 3 to get 57.
Subtract 57 from 71 to get remainder `(71-57=14)`.
Step-3 :Now, bring down 6 from the dividend, to make 146
Step-4 :19 goes into 146 (7-times). Put a 7 in the next place of quotient and multiply 19 by 7 to get 133.
Subtract 133 from 146 to get remainder `(146-133=13)`.
| | 3 | 7 | | |
19 | 7 | 1 | 6 | 8 | 9 |
− | 5 | 7 | | | | =19 × 3 |
| 1 | 4 | 6 | | | |
− | 1 | 3 | 3 | | | =19 × 7 |
| | 1 | 3 | | | |
Step-5 :Now, bring down 8 from the dividend, to make 138
| | 3 | 7 | | |
19 | 7 | 1 | 6 | 8 | 9 |
− | 5 | 7 | | | | =19 × 3 |
| 1 | 4 | 6 | | | |
− | 1 | 3 | 3 | | | =19 × 7 |
| | 1 | 3 | 8 | | |
Step-6 :19 goes into 138 (7-times). Put a 7 in the next place of quotient and multiply 19 by 7 to get 133.
Subtract 133 from 138 to get remainder `(138-133=5)`.
| | 3 | 7 | 7 | |
19 | 7 | 1 | 6 | 8 | 9 |
− | 5 | 7 | | | | =19 × 3 |
| 1 | 4 | 6 | | | |
− | 1 | 3 | 3 | | | =19 × 7 |
| | 1 | 3 | 8 | | |
| − | 1 | 3 | 3 | | =19 × 7 |
| | | | 5 | | |
Step-7 :Now, bring down 9 from the dividend, to make 59
| | 3 | 7 | 7 | |
19 | 7 | 1 | 6 | 8 | 9 |
− | 5 | 7 | | | | =19 × 3 |
| 1 | 4 | 6 | | | |
− | 1 | 3 | 3 | | | =19 × 7 |
| | 1 | 3 | 8 | | |
| − | 1 | 3 | 3 | | =19 × 7 |
| | | | 5 | 9 | |
Step-8 :19 goes into 59 (3-times). Put a 3 in the next place of quotient and multiply 19 by 3 to get 57.
Subtract 57 from 59 to get remainder `(59-57=2)`.
| | 3 | 7 | 7 | 3 |
19 | 7 | 1 | 6 | 8 | 9 |
− | 5 | 7 | | | | =19 × 3 |
| 1 | 4 | 6 | | | |
− | 1 | 3 | 3 | | | =19 × 7 |
| | 1 | 3 | 8 | | |
| − | 1 | 3 | 3 | | =19 × 7 |
| | | | 5 | 9 | |
| | | − | 5 | 7 | =19 × 3 |
| | | | | 2 | |