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Numerical differentiation using Newton's Divided Difference formula
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Method
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 x =
  1. x24910
    f(x)456711980
    and x=5
  2. x35112737
    f(x)-13238991731535606
    and x=10
  3. x0145
    f(x)432439
    and x=2
f(x) =
x1 = and x2 =
 x =
Step value (h) =  OR  Interval (N) =
=
  1. `f(x)=2x^3-4x+1`
    x1 = 2 and x2 = 4
    x = 3
    Interval N = 5
  2. `f(x)=x^3-x+1`
    x1 = 2 and x2 = 4
    x = 3
    Interval N = 5
  3. `f(x)=x^3+x+2`
    x1 = 2 and x2 = 4
    x = 3
    Interval N = 5
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