|
Method and examples
|
|
Method
|
|
|
Equation of line passing through point of intersection of the two lines and having slope
|
|
1. Distance, Slope of two points
|
|
1. Find the distance between the points `A(5,-8)` and `B(-7,-3)`
2. Find the slope of the line joining points `A(4,-8)` and `B(5,-2)`
A
(
,
)
,
B
(
,
)
|
|
` - `A(5,-8),B(-7,-3)`
- `A(7,-4),B(-5,1)`
- `A(-6,-4),B(9,-12)`
- `A(1,-3),B(4,-6)`
- `A(-5,7),B(-1,3)`
- `A(-8,6),B(2,0)`
- `A(0,0),B(7,4)`
|
|
|
Find the value of x or y
|
|
3. If distance between the points (5,3) and (x,-1) is 5, then find the value of x.
A
(
,
)
,
B
(
,
)
,
Distance =
|
|
- `A(5,3),B(x,-1)`, distance `=5`
- `A(x,-1),B(3,2)`, distance `=5`
- `A(x,2),B(3,-6)`, distance `=10`
- `A(x,1),B(-1,5)`, distance `=5`
- `A(x,7),B(1,15)`, distance `=10`
- `A(1,x),B(-3,5)`, distance `=5`
- `A(x,0),B(4,8)`, distance `=10`
|
|
|
4. If slope of the line joining points `A(x,0), B(-3,-2)` is `2/7`, find the value of `x`
A
(
,
)
,
B
(
,
)
,
Slope =
|
|
- `A(x,0),B(-3,-2)`, slope `=2/7`
- `A(2,x),B(-3,7)`, slope `=1`
- `A(x,5),B(-1,2)`, slope `=3/4`
- `A(2,5),B(x,3)`, slope `=2`
- `A(x,2),B(6,-8)`, slope `=-5/4`
- `A(-2,x),B(5,-7)`, slope `=-1`
- `A(2,3),B(x,6)`, slope `=3/5`
- `A(-3,4),B(5,x)`, slope `=-5/4`
- `A(0,x),B(5,-2)`, slope `=-9/5`
|
|
2. Points are Collinear or Triangle or Quadrilateral form
|
|
Show that the points are the vertices of
|
Find `A(0,0), B(2,2), C(0,4), D(-2,2)` are vertices of a square or not
A
(
,
)
,
B
(
,
)
,
C
(
,
)
,
D
(
,
)
|
|
- `A(1,5),B(2,3),C(-2,-11)` are collinear points
- `A(1,-3),B(2,-5),C(-4,7)` are collinear points
- `A(-1,-1),B(1,5),C(2,8)` are collinear points
- `A(0,-1),B(3,5),C(5,9)` are collinear points
- `A(2,8),B(1,5),C(0,2)` are collinear points
- `A(-1,-1),B(1,5),C(2,8)` are collinear points
- `A(0,-1),B(3,5),C(5,9)` are collinear points
- `A(2,8),B(1,5),C(0,2)` are collinear points
- `A(0,0),B(0,3),C(4,0)` are vertices of a right angle triangle
- `A(-2,-2),B(-1,2),C(3,1)` are vertices of a right angle triangle
- `A(-3,2),B(1,2),C(-3,5)` are vertices of a right angle triangle
- `A(2,5),B(8,5),C(5,10.196152)` are vertices of an equilateral triangle
- `A(2,2),B(-2,4),C(2,6)` are vertices of an isosceles triangle
- `A(0,0),B(2,0),C(-4,0),D(-2,0)` are collinear points
- `A(3,2),B(5,4),C(3,6),D(1,4)` are vertices of a square
- `A(0,0),B(2,2),C(0,4),D(-2,2)` are vertices of a square
- `A(1,-1),B(-2,2),C(4,8),D(7,5)` are vertices of a rectangle
- `A(0,-4),B(6,2),C(3,5),D(-3,-1)` are vertices of a rectangle
- `A(3,0),B(4,5),C(-1,4),D(-2,-1)` are vertices of a rhombus
- `A(2,3),B(7,4),C(8,7),D(3,6)` are vertices of a parallelogram
- `A(1,5),B(1,4),C(-1,3),D(-1,4)` are vertices of a parallelogram
|
3. Find Ratio of line joining AB and is divided by P
|
|
1. Find the ratio in which the point P(3/4, 5/12) divides the line segment joining the points A(1/2, 3/2) and B(2, -5)
P
(
,
)
,
A
(
,
)
,
B
(
,
)
|
|
- `P(3/4,5/12),A(1/2,3/2),B(2,-5)`
- `P(-1,6),A(3,10),B(6,-8)`
- `P(-2,3),A(-3,5),B(4,-9)`
- `P(3,10),A(5,12),B(2,9)`
- `P(6,17),A(1,-3),B(3,5)`
- `P(12,23),A(2,8),B(6,14)`
- `P(3,10),A(5,12),B(2,9)`
- `P(6,17),A(1,-3),B(3,5)`
- `P(12,23),A(2,8),B(6,14)`
- `P(17/5,47/5),A(5,13),B(1,4)`
|
|
|
2. Write down the co-ordinates of the point P that divides the line joining A(-4,1) and B(17,10) in the ratio 1:2
A
(
,
)
,
B
(
,
)
,
ratio =
: ,
|
|
- `A(5,13),B(1,4),m:n=2:3`
- `A(-4,1),B(17,10),m:n=1:2`
- `A(5,12),B(2,9),m:n=2:1`
- `A(2,8),B(6,14),m:n=5:3` Externally
- `A(1,-3),B(3,5),m:n=5:3` Externally
|
|
|
3. In what ratio does the x-axis divide the join of `A(2,-3)` and `B(5,6)`? Also find the coordinates of the point of intersection.
A
(
,
)
,
B
(
,
)
,
divided by
|
|
- `A(2,-3),B(5,6)` divided by x-axis
- `A(1,2),B(2,3)` divided by x-axis
- `A(5,-6),B(-1,-4)` divided by y-axis
- `A(-2,1),B(4,5)` divided by y-axis
- `A(2,1),B(7,6)` divided by x-axis
- `A(2,-4),B(-3,6)` divided by y-axis
|
|
|
4. Find the ratio in which the point `P(x,4)` divides the line segment joining the points `A(2,1)` and `B(7,6)`? Also find the value of `x`.
P
(
,
)
,
A
(
,
)
,
B
(
,
)
,
|
|
- `P(x,2),A(12,5),B(4,-3)`
- `P(11,y),A(15,5),B(9,20)`
- `P(-3,y),A(-5,-4),B(-2,3)`
- `P(-4,y),A(-6,10),B(3,-8)`
- `P(x,4),A(2,1),B(7,6)`
- `P(x,0),A(2,-4),B(-3,6)`
- `P(0,y),A(2,-4),B(-3,6)`
|
|
4. Find Midpoint or Trisection points or equidistant points on X-Y axis
|
|
1. Find the coordinates of the midpoint of the line segment joining the points `A(-5,4)` and `B(7,-8)`
2. Find the trisectional points of line joining `A(-3,-5)` and `B(-6,-8)`
3. Find the point on the x-axis which is equidistant from `A(5,4)` and `B(-2,3)`
4. Find the point on the y-axis which is equidistant from `A(6,5)` and `B(-4,3)`
A
(
,
)
,
B
(
,
)
|
|
- `A(-5,4),B(7,-8)`
- `A(2,1),B(1,-3)`
- `A(2,1),B(5,3)`
- `A(3,-5),B(1,1)`
- `A(1,-1),B(-5,-3)`
- `A(-7,-3),B(5,3)`
|
5. Find Centroid, Circumcenter, Area of a triangle
|
|
1. Find the centroid of a triangle whose vertices are `A(4,-6),B(3,-2),C(5,2)`
2. Find the circumcentre of a triangle whose vertices are `A(-2,-3),B(-1,0),C(7,-6)`
3. Using determinants, find the area of the triangle with vertices are `A(-3,5),B(3,-6),C(7, 2)`
4. Using determinants show that the following points are collinear `A(2,3),B(-1,-2),C(5,8)`
A
(
,
)
,
B
(
,
)
,
C
(
,
)
|
|
- `A(4,-6),B(3,-2),C(5,2)`
- `A(3,-5),B(-7,4),C(10,-2)`
- `A(4,-8),B(-9,7),C(8,13)`
- `A(3,-7),B(-8,6),C(5,10)`
- `A(2,4),B(6,4),C(2,0)`
|
6. Find the equation of a line using slope, point, X-intercept, Y-intercept
|
|
1. Find the equation of a straight line passing through `A(-4,5)` and having slope `-2/3`
A
(
,
)
,
Slope :
|
|
- `A(-4,5)`,slope`=-2/3`
- `A(4,5)`,slope`=1`
- `A(-2,3)`,slope`=-4`
- `A(-1,2)`,slope`=-5/4`
- `A(0,3)`,slope`=2`
- `A(0,0)`,slope`=1/4`
- `A(5,4)`,slope`=1/2`
|
|
|
2. Find the equation of a straight line passing through the points `A(7,5)` and `B(-9,5)`
A
(
,
)
,
B
(
,
)
|
|
- `A(7,5),B(-9,5)`
- `A(-1,1),B(2,-4)`
- `A(-5,-6),B(3,10)`
- `A(3,-5),B(4,-8)`
- `A(-1,-4),B(3,0)`
- `A(7,8),B(1,0)`
- `A(6,4),B(-1,5)`
- `A(2,3),B(7,6)`
- `A(-3,4),B(5,-6)`
- `A(0,7),B(5,-2)`
- `A(0,0),B(-4,-6)`
- `A(3,5),B(6,4)`
|
|
|
|
|
|
|
|
4. Find the slope, x-intercept and y-intercept of the line joining the points `A(1,3)` and `B(3,5)`
A
(
,
)
,
B
(
,
)
|
|
- `A(1,3),B(3,5)`
- `A(4,-8),B(5,-2)`
- `A(7,1),B(8,9)`
- `A(4,8),B(5,5)`
- `A(7,8),B(1,0)`
- `A(6,4),B(-1,5)`
- `A(2,3),B(7,6)`
- `A(-3,4),B(5,-6)`
- `A(0,7),B(5,-2)`
- `A(0,0),B(-4,-6)`
- `A(3,5),B(6,4)`
- `A(3,-5),B(-7,9)`
|
|
8. Find the equation of a line passing through point of intersection of two lines and slope or a point
|
|
1. Find the equation of a line passing through the point of intersection of lines `3x+4y=7` and `x-y+2=0` and having slope 5
|
|
Line-1 : ,
|
Line-2 : ,
|
Slope :
|
|
- Line-1`:x-4y+18=0`,Line-2`:x+y-12=0`,slope`=2`
- Line-1`:2x+3y+4=0`,Line-2`:3x+6y-8=0`,slope`=2`
- Line-1`:x=3y`,Line-2`:3x=2y+7`,slope`=-1/2`
- Line-1`:x-4y+18=0`,Line-2`:x+y-12=0`,slope`=2`
- Line-1`:2x+3y+4=0`,Line-2`:3x+6y-8=0`,slope`=2`
- Line-1`:x=3y`,Line-2`:3x=2y+7`,slope`=-1/2`
|
|
|
2. Find the equation of a line passing through the point of intersection of lines `4x+5y+7=0` and `3x-2y-12=0` and point `A(3,1)`
|
|
Line-1 : ,
|
Line-2 : ,
|
A
(
,
)
|
|
- Line-1`:x+y+1=0`,Line-2`:3x+y-5=0`,`A(1,-3)`
- Line-1`:4x+5y+7=0`,Line-2`:3x-2y-12=0`,`A(3,1)`
|
|
9. Find the equation of a line passing through a point and parallel or perpendicular to Line-2
|
|
1. Find the equation of the line passing through the point `A(5,4)` and parallel to the line `2x+3y+7=0`
2. Find the equation of the line passing through the point `A(1,1)` and perpendicular to the line `2x-3y+2=0`
A
(
,
)
,
Line-2 :
|
|
- `A(5,4)`,Line`:2x+3y+7=0`
- `A(1,1)`,Line`:2x-3y+2=0`
- `A(2,3)`,Line`:2x-3y+8=0`
- `A(2,-5)`,Line`:2x-3y-7=0`
|
|
|
3. Find the equation of the line passing through the point `A(1,3)` and parallel to line passing through the points `B(3,-5)` and `C(-6,1)`
4. Find the equation of the line passing through the point `A(5,5)` and perpendicular to the line passing through the points `B(1,-2)` and `C(-5,2)`
A
(
,
)
,
B
(
,
)
,
C
(
,
)
,
|
|
- `A(1,3),B(3,-5),C(-6,1)`
- `A(4,-5),B(3,7),C(-2,4)`
- `A(-1,3),B(0,2),C(4,5)`
- `A(2,-3),B(1,2),C(-1,5)`
- `A(4,2),B(1,-1),C(3,2)`
- `A(5,5),B(1,-2),C(-5,2)`
|
|
12. Reflection of points about x-axis, y-axis, origin
|
|
Find Reflection of points A(0,0),B(2,2),C(0,4),D(-2,2) and Reflection about X,Y,O
A
(
,
)
,
B
(
,
)
,
C
(
,
)
,
D
(
,
)
,
Reflection about
|
|
- `A(-2,-2),B(-1,2),C(3,1)` and Reflection about x
- `A(2,3),B(7,4),C(8,7),D(3,6)` and Reflection about y
- `A(1,-1),B(-2,2),C(4,8),D(7,5)` and Reflection about o
- `A(3,0),B(4,5),C(-1,4),D(-2,-1)` and Reflection about x,y
- `A(3,2),B(5,4),C(3,6),D(1,4)` and Reflection about y,x
- `A(-1,-1),B(1,5),C(2,8)` and Reflection about y=x
- `A(-3,2),B(1,2),C(-3,5)` and Reflection about y=-x
- `A(0,-1),B(3,5),C(5,9)` and Reflection about x=2
- `A(2,8),B(1,5),C(0,2)` and Reflection about y=2
- `A(0,0),B(2,2),C(0,4),D(-2,2)` and Reflection about x+3y-7=0
|
|
Mode =
|
Decimal Place =
|
|
|
|
Solution
|
Solution provided by AtoZmath.com
|
|
Equation of line passing through point of intersection of the two lines and having slope calculator
|
1. Find the equation of a line passing through the point of intersection of lines `x-4y+18=0` and `x+y-12=0` and having slope `2`
2. Find the equation of a line passing through the point of intersection of lines `2x+3y+4=0` and `3x+6y-8=0` and having slope `2`
3. Find the equation of a line passing through the point of intersection of lines `x=3y` and `3x=2y+7` and having slope `-1/2`
|
Example1. Find the equation of a line passing through the point of intersection of lines `x-4y+18=0` and `x+y-12=0` and having slope `2`Solution:The point of intersection of the lines can be obtainted by solving the given equations `x-4y+18=0` `:.x-4y=-18` and `x+y-12=0` `:.x+y=12` `x-4y=-18 ->(1)` `x+y=12 ->(2)` Substracting `=>-5y=-30` `=>5y=30` `=>y=30/5` `=>y=6` Putting `y=6` in equation `(2)`, we have `x+6=12` `=>x=12-6` `=>x=6` `:.x=6" and "y=6` `:. (6,6)` is the intersection point of the given two lines. The equation of a line with slope m and passing through `(x_1,y_1)` is `y-y_1=m(x-x_1)` Here Point `(x_1,y_1)=(6,6)` and Slope `m=2` (given) `:. y-6=2(x-6)` `:. y -6=2x -12` `:. 2x-y-6=0` Hence, The equation of line is `2x-y-6=0`
2. Find the equation of a line passing through the point of intersection of lines `2x+3y+4=0` and `3x+6y-8=0` and having slope `2`Solution:The point of intersection of the lines can be obtainted by solving the given equations `2x+3y+4=0` `:.2x+3y=-4` and `3x+6y-8=0` `:.3x+6y=8` `2x+3y=-4 ->(1)` `3x+6y=8 ->(2)` equation`(1) xx 3 =>6x+9y=-12` equation`(2) xx 2 =>6x+12y=16` Substracting `=>-3y=-28` `=>3y=28` `=>y=28/3` Putting `y=28/3 ` in equation `(1)`, we have `2x+3(28/3)=-4` `=>2x=-4-28` `=>2x=-32` `=>x=-16` `:.x=-16" and "y=28/3` `:. (-16,28/3)` is the intersection point of the given two lines. The equation of a line with slope m and passing through `(x_1,y_1)` is `y-y_1=m(x-x_1)` Here Point `(x_1,y_1)=(-16,28/3)` and Slope `m=2` (given) `:. y-28/3=2(x+16)` `:. y -28/3=2x +32` `:. 2x-y+124/3=0` `:. 6x-3y+124=0` Hence, The equation of line is `6x-3y+124=0`
3. Find the equation of a line passing through the point of intersection of lines `x=3y` and `3x=2y+7` and having slope `-1/2`Solution:The point of intersection of the lines can be obtainted by solving the given equations `x=3y` `:.x-3y=0` and `3x=2y+7` `:.3x-2y=7` `x-3y=0 ->(1)` `3x-2y=7 ->(2)` equation`(1) xx 3 =>3x-9y=0` equation`(2) xx 1 =>3x-2y=7` Substracting `=>-7y=-7` `=>7y=7` `=>y=7/7` `=>y=1` Putting `y=1` in equation `(2)`, we have `3x-2(1)=7` `=>3x=7+2` `=>3x=9` `=>x=3` `:.x=3" and "y=1` `:. (3,1)` is the intersection point of the given two lines. The equation of a line with slope m and passing through `(x_1,y_1)` is `y-y_1=m(x-x_1)` Here Point `(x_1,y_1)=(3,1)` and Slope `m=-1/2` (given) `:. y-1=-1/2(x-3)` `:. 2(y-1)=-1(x-3)` `:. 2y -2=-x +3` `:. x+2y-5=0` Hence, The equation of line is `x+2y-5=0`
|
|
|
|
|