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Educational Level Secondary school, High school and College
Program Purpose Provide step by step solutions of your problems using online calculators (online solvers)
Problem Source Your textbook, etc

1. Coordinate Geometry

2. Graphs
1. Graphs - Plotting of mathematical functions f(x) or f(y)

2. Graph - Using Points and Slope
2.1 Points : (3,-5),(5,3)
2.2 Points on X-axis : -3,5,12,-7,0
2.3 Points on Y-axis : -3,5,12,-7,0
2.4 Lines : x=-3y+5; 2x+y=1; x+2y<=5; x+y>=15
2.5 Line using Slope & point : Slope=7 and Point=(4,6)
2.6 Line using Slope & Y-Intercept : Slope=2 and Y-Intercept=-4
2.7 Line passing through two points : Point1=(3,-5) and Point2=(5,3)

3. Circle
4. Ellipse
5. Parabola
6. Hyperbola
7. Polar Graph

3. Area
1. Area of a Circle
2. Area of a Semi-Circle
3. Area of a Regular Hexagon
4. Area of a Square
5. Area of a Rectangle
6. Area of a Parallelogram
7. Area of a Rhombus
8. Area of a Trapezium
9. Area of a Scalene Triangle
10. Area of a Rightangle Triangle
11. Area of a Equilateral Triangle
12. Area of a Isosceles Triangle
13. Area of a Sector Segment

4. Volume
1. Volume of a Cuboid
2. Volume of a Cube
3. Volume of a Cylinder
4. Volume of a Cone
5. Volume of a Sphere
6. Volume of a Hemi-Sphere

Radius of Circle, Diameter of Circle, Circumference of Circle, Perimeter of Circle, Area of Circle,
Radius of Semi-Circle, Diameter of Semi-Circle, Circumference of Semi-Circle, Perimeter of Semi-Circle, Area of Semi-Circle,
Side of RegularHexagon, Perimeter of RegularHexagon, Area of RegularHexagon,
Side(a) of Square, Diagonal of Square, Perimeter of Square, Area of Square,
Length of Rectangle, Breadth of Rectangle, Diagonal of Rectangle, Perimeter of Rectangle, Area of a Rectangle,
Perimeter of Parallelogram, Area of Parallelogram,
Perimeter of Rhombus, Area of Rhombus,
Perimeter of Trapezium, Area of Trapezium,
Perimeter of Scalene Triangle, Area of Scalene Triangle,
BC of Rightangle Triangle, AC of Rightangle Triangle, Perimeter of Rightangle Triangle, Area of Rightangle Triangle,
Side of Equilateral Triangle, Perimeter of Equilateral Triangle, Area of Equilateral Triangle,
b of Isoceles Triangle, h of Isoceles Triangle, Perimeter of Isoceles Triangle, Area of Isoceles Triangle,
Radius of SectorSegment, angle of measure of SectorSegment, length of arc of SectorSegment, area of minor sector of SectorSegment,

Diagonal of Cuboid, Curved Surface Area of Cuboid, Total Surface Area of Cuboid, Volume of Cuboid,
Diagonal of Cube, Curved Surface Area of Cube, Total Surface Area of Cube, Volume of Cube,
Curved Surface Area of Cylinder, Total Surface Area of Cylinder, Volume of Cylinder,
Slant Height(l) of Cone, Height(h) of Cone, Curved Surface Area of Cone, Total Surface Area of Cone, Volume of Cone,
Radius of Sphere, Diameter of Sphere, Curved Surface Area of Sphere, Total Surface Area of Sphere, Volume of Sphere,
Radius of Hemi-Sphere, Diameter of Hemi-Sphere, Curved Surface Area of Hemi-Sphere, Total Surface Area of Hemi-Sphere, Volume of Hemi-Sphere,


5. Pythagorean Theorem


1. General Graph
1. `y = x`
2. `y <= sin(x)`
3. `y >= cos(x)`
4. `y = sqrt(x)`
5. `y <= sqrt(x^3-3x)`
6. `y >= |x|`
7. `y = x^3-x`
8. `y <= (e^x-e^(-x))/2`

1. `x = sin(y)`
2. `x <= cos(y)`
3. `x >= sqrt(y)`
4. `x = sqrt(y^3-3y)`
5. `x <= |y|`
6. `x >= sin(y)^3+cos(y)^3`
7. `x = y+sin(y)`
8. `x <= (sin(9y)+sin(10y))*sin(0.1y)`

2. Graph - Using Points and Slope
1. Points
like (3,-5),(5,3)

2. Points on X-axis
like -3,5,12,-7,0

3. Points on Y-axis
like -3,5,12,-7,0

4. Lines
like x=-3y+5; 2x+y=1; x+2y<=5; x+y>=15

5. Line using Slope & point
like Slope=7 and Point=(4,6)

6. Line using Slope & Y-Intercept
like Slope=2 and Y-Intercept=-4

7. Line passing through two points
like Point1=(3,-5) and Point2=(5,3)

 
3. Circle
1. Circle-1
`X^2 + Y^2 = 9`

2. Circle-2
`(X+1)^2 + Y^2 = 12`

3. Circle-3
`X^2 + (Y-2)^2 = 15`

4. Circle-4
`(X+1)^2 + (Y-2)^2 = 9`

4. Ellipse
1. Ellipse-1
`X^2/4 + Y^2/9 = 9`

2. Ellipse-2
`(X+1)^2/4 + Y^2/9 = 12`

3. Ellipse-3
`X^2/4 + (Y-2)^2/9 = 15`

4. Ellipse-4
`(X+1)^2/4 + (Y-2)^2/9 = 9`

 
5. Parabola
1. Parabola-1
`Y = 3X^2`

2. Parabola-2
`Y = 3X^2 + 1`

3. Parabola-3
`Y = 3(X+1)^2`

4. Parabola-4
`Y = 3(X+1)^2 + 1`

5. Parabola-5
`X = 3Y^2`

6. Parabola-6
`X = 3Y^2 + 1`

7. Parabola-7
`X = 3(Y+1)^2`

8. Parabola-8
`X = 3(Y+1)^2 + 1`
6. Hyperbola
1. Hyperbola-1
`X^2/4 - Y^2/9 = 9`

2. Hyperbola-2
`2. (X+1)^2/4 - Y^2/9 = 12`

3. Hyperbola-3
`X^2/4 - (Y-2)^2/9 = 15`

4. Hyperbola-4
`(X+1)^2/4 - (Y-2)^2/9 = 9`

5. Hyperbola-5
`Y^2/4 - X^2/9 = 9`

6. Hyperbola-6
`(Y+1)^2/4 - X^2/9 = 12`

7. Hyperbola-7
`Y^2/4 - (X-2)^2/9 = 15`

8. Hyperbola-8
`(Y+1)^2/4 - (X-2)^2/9 = 9`

 
7. Polar Graph
1. `R = 4*cos(2*t)`
2. `R = 4*sin(2*t)`
3. `R = 2-4*sin(2*t)`
4. `R = 2-4*cos(2*t)`
5. `R = 2+4*cos(2*t)`
6. `R = 2+4*sin(2*t)`

8. Statistics Graph
1. Histogram
2. Frequency Polygon
3. Frequency Curve
4. Less than type cumulative frequency curve
5. More than type cumulative frequency curve
1. The frequency distribution of the marks obtained by 100 students in a test of Mathematics carrying 50 marks is given below.
Draw Histogram, Frequency Polygon, Frequency Curve, Less than type cumulative frequency curve and More than type cumulative frequency curve of the data.

Marks obtained0 - 910 - 1920 - 2930 - 3940 - 49
number of students815204512
1. Histogram 2. Frequency Polygon
3. Frequency Curve 4. Less than type cumulative frequency curve
5. More than type cumulative frequency curve
 
1. Circle
Area `(A) = pi r^2`
Circumference `(C) = 2 pi r = pi d`
Diameter `(d) = 2 r`


I know that for a circle Radius = 10 . From this find out Area of the circle.

`"Here radius " (r)=10 "(Given)"`

``

`"Diameter " (d)= 2 * r`

` = 2 * 10`

` = 20`


`"Perimeter" = 2 pi r`

` = 2 * 22/7 * 10`

` = 440/7`


`Area = pi r^2`

` = 22/7 * (10)^2`

` = 2200/7`
2. Semi-Circle
Area `(A) = 1/2 pi r^2`
Circumference `(C) = pi r = (pi d)/2`
Perimeter `(P) = pi r + 2 r`
Diameter `(d) = 2 r`


I know that for a Semi-Circle Radius = 10 . From this find out Area of the Semi-Circle.

`"Here radius "(r)=10" (Given)"`

``

`"Diameter "(d)= 2 r`

` = 2 * 10`

` = 20`

``

`"Circumference" = pi r`

` = 22/7 * 10`

` = 220/7`


`"Perimeter" = pi r + 2 r`

` = 22/7 * 10 + 2 * 10`

` = 220/7 + 20`

` = 360/7`


`"Area" = (pi r^2)/2`

` = (22/7 * (10)^2)/2`

` = 1100/7`
 
3. Regular Hexagon
Perimeter `(P) = 6 a`
Area `(A) = sqrt(3)/4 xx 6 xx a^2`


I know that for a Regular Hexagon Side = 10 . From this find out Area of the Regular Hexagon.

`"Here Side "(a)=10" (Given)"`


`"Perimeter" = 6 a`

` = 6 * 10`

` = 60`


`"Area" = sqrt(3)/4 * 6 * a^2`

` = sqrt(3)/4 * 6 * 10^2`

` = 259.8076`
4. Square
Diagonal `(d) = sqrt(2) a`
Perimeter `(P) = 4a`
Area `(A) = a^2 = d^2/2`


I know that for a square Side(a) = 10 . From this find out Area of the square.

`"Here a" = 10" (Given)"`

`"Diagonal" = sqrt(2) * "a"`

` = sqrt(2) * 10`

` = 14.1421`


`"Perimeter" = 4 * "a"`

` = 4 * 10`

` = 40`


`"Area" = "a"^2`

` = 10^2`

` = 100`
 
5. Rectangle
Diagonal `(d) = sqrt(l^2 + b^2)`
Perimeter `(P) = 2(l+b)`
Area `(A) = l b`


I know that for a rectangle Length = 5 and Breadth = 12 . From this find out Area of the rectangle.

`"Here one-Side " (l) = 5" and other-Side " (b) = 12" (Given)"`

`"Diagonal" = sqrt(l^2 + b^2)`

` = sqrt(5^2 + 12^2)`

` = sqrt(25 + 144)`

` = sqrt(169)`

` = 13`


`"Perimeter" = 2 * "(sum of Sides)"`

` = 2 * (5 + 12)`

` = 34`


`"Area = Product of Sides"`

` = 5 * 12`

` = 60`
6. Parallelogram
Area `(A) = ah`
Perimeter `(P) = 2a + 2b`


I know that for a parallelogram a = 9 , b = 22 and h = 14 . From this find out Area of the parallelogram.

`"Here " a=9, b=22, h=14" (Given)"`


`"Perimeter" = 2 * (a + b)`

` = 2 * (9 + 22) `

` = 62`


`"Area" = a * h`

` = 9 * 14`

` = 126`
 
7. Rhombus
Radius `(r_1) = (d_1)/2`
Radius `(r_2) = (d_2)/2`
Side `(a) = sqrt(r_1^2 + r_2^2)`
Perimeter `(P) = 4 a`
Area `(SA) = (d_1 d_2)/2`


I know that for a rhombus d1 = 10 and d2 = 24 . From this find out Area of the rhombus.

`"Here, we have " d_1 = 10" and " d_2 = 24" (Given)"`


`a^2 = (d_1/2)^2 + (d_2/2)^2`

`a^2 = (10/2)^2 + (24/2)^2`

`a^2 = (5)^2 + (12)^2`

`a^2 = 169`

`a = 13`

`"Perimeter" = 4 * a`

` = 4 * 13`

` = 52`


`"Area" = 1/2 " (Product of diagonals)"`

` = 1/2 * d_1 * d_2`

` = 1/2 * 10 * 24`

` = 120`
8. Trapezium
Area `(A) = h/2 (a + b)`
Perimeter `(P) = a + b + c + d`


I know that for a trapezium a = 22 , b = 18 , c = 16 , d = 16 and h = 4 . From this find out Area of the trapezium.

`"Here " a=22, b=18, c=16, d=16, h=4" (Given)"`


`"Perimeter" = a + b + c + d`

` = 22 + 18 + 16 + 16 `

` = 72`


`"Area" = (a + b) * h/2`

` = (22 + 18) * 4/2`

` = 80`
 
9. Scalene Triangle
Perimeter `(P) = a+b+c`
`S = P/2 = (a+b+c)/2`
Area `(A) = sqrt(S (S - a) (S - b) (S - c))`


I know that for a scalene Triangles a = 3 , b = 4 and c = 5 . From this find out Area of the scalene Triangles.

`"Here " a=3, b=4, c=5" (Given)"`


`"We know that,"`

`"Perimeter" = a + b + c`

` = 3 + 4 + 5`

` = 12`

` `

`"Semi-Perimeter" = s = (a + b + c)/2`

` = 12/2`

` = 6`


`"Here " a=3, b=4, c=5" and semi-Perimeter" = 6`

`"We know that,"`

`"Area" = sqrt(s (s - a) (s - b) (s - c))`

` = sqrt(6 (6 - 3) (6 - 4) (6 - 5))`

` = 6`
10. Right angle Triangle
Diagonal `(d) = sqrt(a^2 + b^2)`
Perimeter `(P) = a+b+c`
Area `(A) = 1/2(a b)`


I know that for a right angle Triangles AB = 5 and BC = 12 . From this find out Area of the right angle Triangles.

`"Here one Side" = 5" and other Side" = 12" (Given)"`

`"We know that,"`

`"In triangle ABC, by Pythagoras' theorem"`

`AC^2 = AB^2 + BC^2`

`AC^2 = 5^2 + 12^2`

`AC^2 = 25 + 144`

`AC^2 = 169`

`AC = 13`


`"Perimeter" = AB + BC + AC`

` = 5 + 12 + 13`

` = 30`

` `


`"Here base" = 5" and height = "12 `

`"We know that,"`

`"Area" = 1/2 * AB * BC`

` = 1/2 * 5 * 12`

` = 30`
 
11. Equilateral Triangle
Perimeter `(P) = 3 a`
Area `(A) = sqrt(3)/4 a^2`


I know that for a equilateral Triangles Side = 6 . From this find out Area of the equilateral Triangles.

`"Here " a = 6" (Given)"`


`"We know that,"`

`"Perimeter" = 3 * a`

` = 3 * 6`

` = 18`


`"We know that,"`

`"Area" = sqrt(3)/4 * a^2`

` = 1.732/4 * 6 * 6`

` = 15.5885`
12. Isosceles Triangle
Height `(h) = sqrt(a^2 - b^2/4)`
Perimeter `(P) = 2 a + b`
Area `(A) = (b h)/2`


I know that for a isosceles Triangles a = 5 and b = 6 . From this find out Area of the isoceles Triangles.

`"Here base " (b) = 6" and equal side " (a) = 5" (Given)"`


`"We know that,"`

`"Perimeter" = (2 * "equal Side") + "third Side"`

` = (2 * a) + b`

` = (2 * 5) + 6`

` = 16`


`"We know that,"`

`"Area" = 1/2 * "base" * "height"`

` = 1/2 * b * (sqrt(a^2 - b^2))/4`

` = 1/2 * 6 * sqrt(5^2 - 6^2)/4`

` = 1/2 * 6 * 4 `

` = 12`
 
13. Sector Segment
Length of the arc `= l = (pi r theta)/180`
Area of a minor sector `= (pi r^2 theta)/360`


I know that for a sector & segment Radius = 10 and angle of measure = 180 . From this find out length of arc of the sector & segment.

`"Here "r = 10" and " theta = 180" (Given)"`

`"Length of the arc " = l = (pi r theta)/180`

`=(22/7 * 10 * 180)/180`

`=31.4286`


`"Area of a minor sector "= (pi r^2 theta)/360`

`=(22/7 * 10^2 * 180)/360`

`=157.1429`
1. Cuboid
Diagonal `(d) = sqrt(l^2+ b^2+ h^2)`
Surface Area `(SA) = 2 (lb + bh + hl)`
Volume `(V) = lbh`



I know that for a cuboid Length = 3 , Breadth = 4 , and Height = 5 . From this find out Volume of the cuboid.

`"Here, we have " l = 3, b=4, h=5" (Given)"`

`"Diagonal"^2 = l^2 + b^2 + h^2`

`"Diagonal"^2 = 3^2 + 4^2 + 5^2`

`"Diagonal"^2 = 50`

`Diagonal = 7.0711`


`"Here, we have " l = 3, b=4, h=5" (Given)"`

`"Volume" = l * b * h`

` = 3 * 4 * 5`

` = 60`


`"Here, we have " l = 3, b=4, h=5" (Given)"`

`"Total Surface Area" = 2 (lb + bh + lh)`

` = 2 * (3 * 4 + 4 * 5 + 3 * 5)`

` = 2 * (47)`

` = 94`


`"Here, we have " l = 3, b=4, h=5" (Given)"`

`"Curved Surface Area" = 2h (l + b)`

` = 2 * 5 (3 + 4)`

` = 70`
2. Cube
diameter `(d) = sqrt(2) l`
Diagonal `= sqrt(3) l`
Surface Area `(SA) = 6 l^2`
Volume `(V) = l^3`


I know that for a cube Length = 3 . From this find out Volume of the cube.

`"Here, we have " l = 3`

`"Diagonal" = sqrt(3) l`

` = sqrt(3) * 3`

` = 5.1962`


`"Here, we have " l = 3`

`"Volume" = l^3`

` = 3^3`

` = 27`


`"Here, we have " l = 3`

`"Total Surface Area" = 6 l^2`

` = 6 * 3^2`

` = 6 * 9`

` = 54`


`"Here, we have " l = 3`

`"Curved Surface Area" = 4 l^2`

` = 4 * 3^2`

` = 4 * 9`

` = 36`
 
3. Cylinder
Curved Surface Area `(CSA) = 2 pi r h`
Total Surface Area `(TSA) = 2 pi r (r + h)`
Volume `(V) = pi r^2 h`


I know that for a cylinder Radius = 3 and Height = 10 . From this find out Curved Surface Area of the cylinder.

`"Here, we have Radius "(r) = 3" and Height "(h) = 10" (Given)"`


`"Volume" = pi r^2 h`

` = pi * 3^2 * 10`

` = 282.7433`


`"Total Surface Area" = 2 pi r (r+h)`

` = 2 * pi * 3 * (3 + 10)`

` = 245.0442`


`"Curved Surface Area" = 2 pi r h`

` = 2 * pi * 3 * 10`

` = 188.4956`
4. Cone
Height `(h) = sqrt(l^2 - r^2)`
Curved Surface Area `(CSA) = pi r l`
Total Surface Area `(TSA) = pi r (l + r)`
Volume `(V) = (pi r^2 h)/3`

I know that for a cone Radius = 3 and Length = 5 . From this find out Volume of the cone.

`"Here, we have Radius "(r) = 3" and Slant Height " (l) = 5" (Given)"`

`l^2 = r^2 + h^2`

`h^2 = l^2 - r^2`

`h^2 = 5^2 - 3^2`

`h^2 = 16`

`h = 4`


`"Volume" = (pi r^2 h)/3`

` = (pi * 3^2 * 4)/3`

` = 37.6991`


`"Total Surface Area" = pi r (l + r)`

` = pi * 3 (5 + 3)`

` = 75.3982`


`"Curved Surface Area" = pi r l`

` = pi * 3 * 5`

` = 47.1239`
 
5. Sphere
Surface Area `(SA) = 4 pi r^2`
Volume `(V) = 4/3 pi r^3`
diameter `(d) = 2r`


I know that for a sphere Radius = 3 . From this find out Volume of the sphere.

`"Here, we have Radius"(r) = 3" (Given)"`


`"Volume" = 4/3 pi r^3`

` = 4/3 * pi * 3^3`

` = 84.823`


`"Total Surface Area" = 4 pi r^2`

` = 4 * pi * 3^2`

` = 113.0973`


`"Curved Surface Area" = 4 pi r^2`

` = 4 * pi * 3^2`

` = 113.0973`
6. Hemi-Sphere
Curved Surface Area `(CSA) = 2 pi r^2`
Total Surface Area `(TSA) = 3 pi r^2`
Volume `(V) = 2/3 pi r^3`
diameter `(d) = 2r`


I know that for a Hemi-Sphere Radius = 3 . From this find out Volume of the Hemi-Sphere.

`"Here, we have Radius " (r) = 3" (Given)"`


`"Volume" = 2/3 pi r^3`

` = 2/3 * pi * 3^3`

` = 56.5487`


`"Total Surface Area" = 3 pi r^2`

` = 3 * pi * 3^2`

` = 84.823`


`"Curved Surface Area" = 2 pi r^2`

` = 2 * pi * 3^2`

` = 56.5487`
 
Pythagorean Theorem : In a right angled triangle, the square of the length of the hypotenuse is equal to the sum of the squares of the lengths of the remaining sides.


i.e. `AC^2 = AB^2 + BC^2`

Using Pythagoras Theorem, Find out AC when AB = 5 and BC = 12
Here AB=5 and BC=12 (Given)
We know that,
In triangle ABC, by Pythagoras' theorem
`AC^2 = AB^2 + BC^2`
`AC^2 = 5^2 + 12^2`
`AC^2 = 25 + 144`
`AC^2 = 169`
`AC = 13`





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