|
Method and examples
|
|
Method
|
|
|
Equation of line passing through a given point and perpendicular to the line passing given points
|
|
1. Distance, Slope of two points
|
|
1. Find the distance between the points `A(5,-8)` and `B(-7,-3)`
2. Find the slope of the line joining points `A(4,-8)` and `B(5,-2)`
A
(
,
)
,
B
(
,
)
|
|
` - `A(5,-8),B(-7,-3)`
- `A(7,-4),B(-5,1)`
- `A(-6,-4),B(9,-12)`
- `A(1,-3),B(4,-6)`
- `A(-5,7),B(-1,3)`
- `A(-8,6),B(2,0)`
- `A(0,0),B(7,4)`
|
|
|
Find the value of x or y
|
|
3. If distance between the points (5,3) and (x,-1) is 5, then find the value of x.
A
(
,
)
,
B
(
,
)
,
Distance =
|
|
- `A(5,3),B(x,-1)`, distance `=5`
- `A(x,-1),B(3,2)`, distance `=5`
- `A(x,2),B(3,-6)`, distance `=10`
- `A(x,1),B(-1,5)`, distance `=5`
- `A(x,7),B(1,15)`, distance `=10`
- `A(1,x),B(-3,5)`, distance `=5`
- `A(x,0),B(4,8)`, distance `=10`
|
|
|
4. If slope of the line joining points `A(x,0), B(-3,-2)` is `2/7`, find the value of `x`
A
(
,
)
,
B
(
,
)
,
Slope =
|
|
- `A(x,0),B(-3,-2)`, slope `=2/7`
- `A(2,x),B(-3,7)`, slope `=1`
- `A(x,5),B(-1,2)`, slope `=3/4`
- `A(2,5),B(x,3)`, slope `=2`
- `A(x,2),B(6,-8)`, slope `=-5/4`
- `A(-2,x),B(5,-7)`, slope `=-1`
- `A(2,3),B(x,6)`, slope `=3/5`
- `A(-3,4),B(5,x)`, slope `=-5/4`
- `A(0,x),B(5,-2)`, slope `=-9/5`
|
|
2. Points are Collinear or Triangle or Quadrilateral form
|
|
Show that the points are the vertices of
|
Find `A(0,0), B(2,2), C(0,4), D(-2,2)` are vertices of a square or not
A
(
,
)
,
B
(
,
)
,
C
(
,
)
,
D
(
,
)
|
|
- `A(1,5),B(2,3),C(-2,-11)` are collinear points
- `A(1,-3),B(2,-5),C(-4,7)` are collinear points
- `A(-1,-1),B(1,5),C(2,8)` are collinear points
- `A(0,-1),B(3,5),C(5,9)` are collinear points
- `A(2,8),B(1,5),C(0,2)` are collinear points
- `A(-1,-1),B(1,5),C(2,8)` are collinear points
- `A(0,-1),B(3,5),C(5,9)` are collinear points
- `A(2,8),B(1,5),C(0,2)` are collinear points
- `A(0,0),B(0,3),C(4,0)` are vertices of a right angle triangle
- `A(-2,-2),B(-1,2),C(3,1)` are vertices of a right angle triangle
- `A(-3,2),B(1,2),C(-3,5)` are vertices of a right angle triangle
- `A(2,5),B(8,5),C(5,10.196152)` are vertices of an equilateral triangle
- `A(2,2),B(-2,4),C(2,6)` are vertices of an isosceles triangle
- `A(0,0),B(2,0),C(-4,0),D(-2,0)` are collinear points
- `A(3,2),B(5,4),C(3,6),D(1,4)` are vertices of a square
- `A(0,0),B(2,2),C(0,4),D(-2,2)` are vertices of a square
- `A(1,-1),B(-2,2),C(4,8),D(7,5)` are vertices of a rectangle
- `A(0,-4),B(6,2),C(3,5),D(-3,-1)` are vertices of a rectangle
- `A(3,0),B(4,5),C(-1,4),D(-2,-1)` are vertices of a rhombus
- `A(2,3),B(7,4),C(8,7),D(3,6)` are vertices of a parallelogram
- `A(1,5),B(1,4),C(-1,3),D(-1,4)` are vertices of a parallelogram
|
3. Find Ratio of line joining AB and is divided by P
|
|
1. Find the ratio in which the point P(3/4, 5/12) divides the line segment joining the points A(1/2, 3/2) and B(2, -5)
P
(
,
)
,
A
(
,
)
,
B
(
,
)
|
|
- `P(3/4,5/12),A(1/2,3/2),B(2,-5)`
- `P(-1,6),A(3,10),B(6,-8)`
- `P(-2,3),A(-3,5),B(4,-9)`
- `P(3,10),A(5,12),B(2,9)`
- `P(6,17),A(1,-3),B(3,5)`
- `P(12,23),A(2,8),B(6,14)`
- `P(3,10),A(5,12),B(2,9)`
- `P(6,17),A(1,-3),B(3,5)`
- `P(12,23),A(2,8),B(6,14)`
- `P(17/5,47/5),A(5,13),B(1,4)`
|
|
|
2. Write down the co-ordinates of the point P that divides the line joining A(-4,1) and B(17,10) in the ratio 1:2
A
(
,
)
,
B
(
,
)
,
ratio =
: ,
|
|
- `A(5,13),B(1,4),m:n=2:3`
- `A(-4,1),B(17,10),m:n=1:2`
- `A(5,12),B(2,9),m:n=2:1`
- `A(2,8),B(6,14),m:n=5:3` Externally
- `A(1,-3),B(3,5),m:n=5:3` Externally
|
|
|
3. In what ratio does the x-axis divide the join of `A(2,-3)` and `B(5,6)`? Also find the coordinates of the point of intersection.
A
(
,
)
,
B
(
,
)
,
divided by
|
|
- `A(2,-3),B(5,6)` divided by x-axis
- `A(1,2),B(2,3)` divided by x-axis
- `A(5,-6),B(-1,-4)` divided by y-axis
- `A(-2,1),B(4,5)` divided by y-axis
- `A(2,1),B(7,6)` divided by x-axis
- `A(2,-4),B(-3,6)` divided by y-axis
|
|
|
4. Find the ratio in which the point `P(x,4)` divides the line segment joining the points `A(2,1)` and `B(7,6)`? Also find the value of `x`.
P
(
,
)
,
A
(
,
)
,
B
(
,
)
,
|
|
- `P(x,2),A(12,5),B(4,-3)`
- `P(11,y),A(15,5),B(9,20)`
- `P(-3,y),A(-5,-4),B(-2,3)`
- `P(-4,y),A(-6,10),B(3,-8)`
- `P(x,4),A(2,1),B(7,6)`
- `P(x,0),A(2,-4),B(-3,6)`
- `P(0,y),A(2,-4),B(-3,6)`
|
|
4. Find Midpoint or Trisection points or equidistant points on X-Y axis
|
|
1. Find the coordinates of the midpoint of the line segment joining the points `A(-5,4)` and `B(7,-8)`
2. Find the trisectional points of line joining `A(-3,-5)` and `B(-6,-8)`
3. Find the point on the x-axis which is equidistant from `A(5,4)` and `B(-2,3)`
4. Find the point on the y-axis which is equidistant from `A(6,5)` and `B(-4,3)`
A
(
,
)
,
B
(
,
)
|
|
- `A(-5,4),B(7,-8)`
- `A(2,1),B(1,-3)`
- `A(2,1),B(5,3)`
- `A(3,-5),B(1,1)`
- `A(1,-1),B(-5,-3)`
- `A(-7,-3),B(5,3)`
|
5. Find Centroid, Circumcenter, Area of a triangle
|
|
1. Find the centroid of a triangle whose vertices are `A(4,-6),B(3,-2),C(5,2)`
2. Find the circumcentre of a triangle whose vertices are `A(-2,-3),B(-1,0),C(7,-6)`
3. Using determinants, find the area of the triangle with vertices are `A(-3,5),B(3,-6),C(7, 2)`
4. Using determinants show that the following points are collinear `A(2,3),B(-1,-2),C(5,8)`
A
(
,
)
,
B
(
,
)
,
C
(
,
)
|
|
- `A(4,-6),B(3,-2),C(5,2)`
- `A(3,-5),B(-7,4),C(10,-2)`
- `A(4,-8),B(-9,7),C(8,13)`
- `A(3,-7),B(-8,6),C(5,10)`
- `A(2,4),B(6,4),C(2,0)`
|
6. Find the equation of a line using slope, point, X-intercept, Y-intercept
|
|
1. Find the equation of a straight line passing through `A(-4,5)` and having slope `-2/3`
A
(
,
)
,
Slope :
|
|
- `A(-4,5)`,slope`=-2/3`
- `A(4,5)`,slope`=1`
- `A(-2,3)`,slope`=-4`
- `A(-1,2)`,slope`=-5/4`
- `A(0,3)`,slope`=2`
- `A(0,0)`,slope`=1/4`
- `A(5,4)`,slope`=1/2`
|
|
|
2. Find the equation of a straight line passing through the points `A(7,5)` and `B(-9,5)`
A
(
,
)
,
B
(
,
)
|
|
- `A(7,5),B(-9,5)`
- `A(-1,1),B(2,-4)`
- `A(-5,-6),B(3,10)`
- `A(3,-5),B(4,-8)`
- `A(-1,-4),B(3,0)`
- `A(7,8),B(1,0)`
- `A(6,4),B(-1,5)`
- `A(2,3),B(7,6)`
- `A(-3,4),B(5,-6)`
- `A(0,7),B(5,-2)`
- `A(0,0),B(-4,-6)`
- `A(3,5),B(6,4)`
|
|
|
|
|
|
|
|
4. Find the slope, x-intercept and y-intercept of the line joining the points `A(1,3)` and `B(3,5)`
A
(
,
)
,
B
(
,
)
|
|
- `A(1,3),B(3,5)`
- `A(4,-8),B(5,-2)`
- `A(7,1),B(8,9)`
- `A(4,8),B(5,5)`
- `A(7,8),B(1,0)`
- `A(6,4),B(-1,5)`
- `A(2,3),B(7,6)`
- `A(-3,4),B(5,-6)`
- `A(0,7),B(5,-2)`
- `A(0,0),B(-4,-6)`
- `A(3,5),B(6,4)`
- `A(3,-5),B(-7,9)`
|
|
8. Find the equation of a line passing through point of intersection of two lines and slope or a point
|
|
1. Find the equation of a line passing through the point of intersection of lines `3x+4y=7` and `x-y+2=0` and having slope 5
|
|
Line-1 : ,
|
Line-2 : ,
|
Slope :
|
|
- Line-1`:x-4y+18=0`,Line-2`:x+y-12=0`,slope`=2`
- Line-1`:2x+3y+4=0`,Line-2`:3x+6y-8=0`,slope`=2`
- Line-1`:x=3y`,Line-2`:3x=2y+7`,slope`=-1/2`
- Line-1`:x-4y+18=0`,Line-2`:x+y-12=0`,slope`=2`
- Line-1`:2x+3y+4=0`,Line-2`:3x+6y-8=0`,slope`=2`
- Line-1`:x=3y`,Line-2`:3x=2y+7`,slope`=-1/2`
|
|
|
2. Find the equation of a line passing through the point of intersection of lines `4x+5y+7=0` and `3x-2y-12=0` and point `A(3,1)`
|
|
Line-1 : ,
|
Line-2 : ,
|
A
(
,
)
|
|
- Line-1`:x+y+1=0`,Line-2`:3x+y-5=0`,`A(1,-3)`
- Line-1`:4x+5y+7=0`,Line-2`:3x-2y-12=0`,`A(3,1)`
|
|
9. Find the equation of a line passing through a point and parallel or perpendicular to Line-2
|
|
1. Find the equation of the line passing through the point `A(5,4)` and parallel to the line `2x+3y+7=0`
2. Find the equation of the line passing through the point `A(1,1)` and perpendicular to the line `2x-3y+2=0`
A
(
,
)
,
Line-2 :
|
|
- `A(5,4)`,Line`:2x+3y+7=0`
- `A(1,1)`,Line`:2x-3y+2=0`
- `A(2,3)`,Line`:2x-3y+8=0`
- `A(2,-5)`,Line`:2x-3y-7=0`
|
|
|
3. Find the equation of the line passing through the point `A(1,3)` and parallel to line passing through the points `B(3,-5)` and `C(-6,1)`
4. Find the equation of the line passing through the point `A(5,5)` and perpendicular to the line passing through the points `B(1,-2)` and `C(-5,2)`
A
(
,
)
,
B
(
,
)
,
C
(
,
)
,
|
|
- `A(-3,5),B(2,5),C(-3,6)`
- `A(5,2),B(2,3),C(3,-1)`
- `A(0,3),B(-3,2),C(9,1)`
- `A(2,-3),B(5,7),C(-6,3)`
- `A(5,7),B(-1,-1),C(-4,1)`
- `A(4,2),B(1,-1),C(3,2)`
- `A(5,5),B(1,-2),C(-5,2)`
|
|
12. Reflection of points about x-axis, y-axis, origin
|
|
Find Reflection of points A(0,0),B(2,2),C(0,4),D(-2,2) and Reflection about X,Y,O
A
(
,
)
,
B
(
,
)
,
C
(
,
)
,
D
(
,
)
,
Reflection about
|
|
- `A(-2,-2),B(-1,2),C(3,1)` and Reflection about x
- `A(2,3),B(7,4),C(8,7),D(3,6)` and Reflection about y
- `A(1,-1),B(-2,2),C(4,8),D(7,5)` and Reflection about o
- `A(3,0),B(4,5),C(-1,4),D(-2,-1)` and Reflection about x,y
- `A(3,2),B(5,4),C(3,6),D(1,4)` and Reflection about y,x
- `A(-1,-1),B(1,5),C(2,8)` and Reflection about y=x
- `A(-3,2),B(1,2),C(-3,5)` and Reflection about y=-x
- `A(0,-1),B(3,5),C(5,9)` and Reflection about x=2
- `A(2,8),B(1,5),C(0,2)` and Reflection about y=2
- `A(0,0),B(2,2),C(0,4),D(-2,2)` and Reflection about x+3y-7=0
|
|
Mode =
|
Decimal Place =
|
|
|
|
Solution
|
Solution provided by AtoZmath.com
|
|
Equation of line passing through a given point and perpendicular to the line passing given points calculator
|
1. Find the equation of the line passing through the point `A(-3,5)` and perpendicular to line passing through the points `B(2,5)` and `C(-3,6)`
2. Find the equation of the line passing through the point `A(5,2)` and perpendicular to line passing through the points `B(2,3)` and `C(3,-1)`
3. Find the equation of the line passing through the point `A(0,3)` and perpendicular to line passing through the points `B(-3,2)` and `C(9,1)`
4. Find the equation of the line passing through the point `A(2,-3)` and perpendicular to line passing through the points `B(5,7)` and `C(-6,3)`
5. Find the equation of the line passing through the point `A(5,7)` and perpendicular to line passing through the points `B(-1,-1)` and `C(-4,1)`
6. Find the equation of the line passing through the point `A(4,2)` and perpendicular to line passing through the points `B(1,-1)` and `C(3,2)`
7. Find the equation of the line passing through the point `A(5,5)` and perpendicular to line passing through the points `B(1,-2)` and `C(-5,2)`
|
Example1. Find the equation of the line passing through the point `A(-3,5)` and perpendicular to line passing through the points `B(2,5)` and `C(-3,6)`Solution:Given points are `A(-3,5)`, `B(2,5)` and `C(-3,6)` When two lines are perpendicular, their slopes are opposite reciprocals of one another or the product of their slopes is -1. We shall first find the slope of `B(2,5)` and `C(-3,6)` Points are `B(2,5),C(-3,6)` `:. x_1=2,y_1=5,x_2=-3,y_2=6` Slope of the line, `m=(y_2-y_1)/(x_2-x_1)` `:. m=(6-5)/(-3-2)` `:. m=(1)/(-5)` `:. m=-1/5` `:.` Slope `=-1/5` `:.` Slope of perpendicular line`=(-1)/(-1/5)=5` (`:' m_1*m_2=-1`) The equation of a line with slope m and passing through `(x_1,y_1)` is `y-y_1=m(x-x_1)` Here Point `(x_1,y_1)=(-3,5)` and Slope `m=5` (given) `:. y-5=5(x+3)` `:. y -5=5x +15` `:. 5x-y+20=0` Hence, The equation of line is `5x-y+20=0`
2. Find the equation of the line passing through the point `A(5,2)` and perpendicular to line passing through the points `B(2,3)` and `C(3,-1)`Solution:Given points are `A(5,2)`, `B(2,3)` and `C(3,-1)` When two lines are perpendicular, their slopes are opposite reciprocals of one another or the product of their slopes is -1. We shall first find the slope of `B(2,3)` and `C(3,-1)` Points are `B(2,3),C(3,-1)` `:. x_1=2,y_1=3,x_2=3,y_2=-1` Slope of the line, `m=(y_2-y_1)/(x_2-x_1)` `:. m=(-1-3)/(3-2)` `:. m=(-4)/(1)` `:. m=-4` `:.` Slope `=-4` `:.` Slope of perpendicular line`=(-1)/(-4)=1/4` (`:' m_1*m_2=-1`) The equation of a line with slope m and passing through `(x_1,y_1)` is `y-y_1=m(x-x_1)` Here Point `(x_1,y_1)=(5,2)` and Slope `m=1/4` (given) `:. y-2=1/4(x-5)` `:. 4(y-2)=(x-5)` `:. 4y -8=x -5` `:. x-4y+3=0` Hence, The equation of line is `x-4y+3=0`
3. Find the equation of the line passing through the point `A(0,3)` and perpendicular to line passing through the points `B(-3,2)` and `C(9,1)`Solution:Given points are `A(0,3)`, `B(-3,2)` and `C(9,1)` When two lines are perpendicular, their slopes are opposite reciprocals of one another or the product of their slopes is -1. We shall first find the slope of `B(-3,2)` and `C(9,1)` Points are `B(-3,2),C(9,1)` `:. x_1=-3,y_1=2,x_2=9,y_2=1` Slope of the line, `m=(y_2-y_1)/(x_2-x_1)` `:. m=(1-2)/(9+3)` `:. m=(-1)/(12)` `:.` Slope `=-1/12` `:.` Slope of perpendicular line`=(-1)/(-1/12)=12` (`:' m_1*m_2=-1`) The equation of a line with slope m and passing through `(x_1,y_1)` is `y-y_1=m(x-x_1)` Here Point `(x_1,y_1)=(0,3)` and Slope `m=12` (given) `:. y-3=12(x-0)` `:. y -3=12x +0` `:. 12x-y+3=0` Hence, The equation of line is `12x-y+3=0`
4. Find the equation of the line passing through the point `A(2,-3)` and perpendicular to line passing through the points `B(5,7)` and `C(-6,3)`Solution:Given points are `A(2,-3)`, `B(5,7)` and `C(-6,3)` When two lines are perpendicular, their slopes are opposite reciprocals of one another or the product of their slopes is -1. We shall first find the slope of `B(5,7)` and `C(-6,3)` Points are `B(5,7),C(-6,3)` `:. x_1=5,y_1=7,x_2=-6,y_2=3` Slope of the line, `m=(y_2-y_1)/(x_2-x_1)` `:. m=(3-7)/(-6-5)` `:. m=(-4)/(-11)` `:. m=4/11` `:.` Slope `=4/11` `:.` Slope of perpendicular line`=(-1)/(4/11)=-11/4` (`:' m_1*m_2=-1`) The equation of a line with slope m and passing through `(x_1,y_1)` is `y-y_1=m(x-x_1)` Here Point `(x_1,y_1)=(2,-3)` and Slope `m=-11/4` (given) `:. y+3=-11/4(x-2)` `:. 4(y+3)=-11(x-2)` `:. 4y +12=-11x +22` `:. 11x+4y-10=0` Hence, The equation of line is `11x+4y-10=0`
5. Find the equation of the line passing through the point `A(5,7)` and perpendicular to line passing through the points `B(-1,-1)` and `C(-4,1)`Solution:Given points are `A(5,7)`, `B(-1,-1)` and `C(-4,1)` When two lines are perpendicular, their slopes are opposite reciprocals of one another or the product of their slopes is -1. We shall first find the slope of `B(-1,-1)` and `C(-4,1)` Points are `B(-1,-1),C(-4,1)` `:. x_1=-1,y_1=-1,x_2=-4,y_2=1` Slope of the line, `m=(y_2-y_1)/(x_2-x_1)` `:. m=(1+1)/(-4+1)` `:. m=(2)/(-3)` `:. m=-2/3` `:.` Slope `=-2/3` `:.` Slope of perpendicular line`=(-1)/(-2/3)=3/2` (`:' m_1*m_2=-1`) The equation of a line with slope m and passing through `(x_1,y_1)` is `y-y_1=m(x-x_1)` Here Point `(x_1,y_1)=(5,7)` and Slope `m=3/2` (given) `:. y-7=3/2(x-5)` `:. 2(y-7)=3(x-5)` `:. 2y -14=3x -15` `:. 3x-2y-1=0` Hence, The equation of line is `3x-2y-1=0`
6. Find the equation of the line passing through the point `A(4,2)` and perpendicular to line passing through the points `B(1,-1)` and `C(3,2)`Solution:Given points are `A(4,2)`, `B(1,-1)` and `C(3,2)` When two lines are perpendicular, their slopes are opposite reciprocals of one another or the product of their slopes is -1. We shall first find the slope of `B(1,-1)` and `C(3,2)` Points are `B(1,-1),C(3,2)` `:. x_1=1,y_1=-1,x_2=3,y_2=2` Slope of the line, `m=(y_2-y_1)/(x_2-x_1)` `:. m=(2+1)/(3-1)` `:. m=(3)/(2)` `:.` Slope `=3/2` `:.` Slope of perpendicular line`=(-1)/(3/2)=-2/3` (`:' m_1*m_2=-1`) The equation of a line with slope m and passing through `(x_1,y_1)` is `y-y_1=m(x-x_1)` Here Point `(x_1,y_1)=(4,2)` and Slope `m=-2/3` (given) `:. y-2=-2/3(x-4)` `:. 3(y-2)=-2(x-4)` `:. 3y -6=-2x +8` `:. 2x+3y-14=0` Hence, The equation of line is `2x+3y-14=0`
7. Find the equation of the line passing through the point `A(5,5)` and perpendicular to line passing through the points `B(1,-2)` and `C(-5,2)`Solution:Given points are `A(5,5)`, `B(1,-2)` and `C(-5,2)` When two lines are perpendicular, their slopes are opposite reciprocals of one another or the product of their slopes is -1. We shall first find the slope of `B(1,-2)` and `C(-5,2)` Points are `B(1,-2),C(-5,2)` `:. x_1=1,y_1=-2,x_2=-5,y_2=2` Slope of the line, `m=(y_2-y_1)/(x_2-x_1)` `:. m=(2+2)/(-5-1)` `:. m=(4)/(-6)` `:. m=-2/3` `:.` Slope `=-2/3` `:.` Slope of perpendicular line`=(-1)/(-2/3)=3/2` (`:' m_1*m_2=-1`) The equation of a line with slope m and passing through `(x_1,y_1)` is `y-y_1=m(x-x_1)` Here Point `(x_1,y_1)=(5,5)` and Slope `m=3/2` (given) `:. y-5=3/2(x-5)` `:. 2(y-5)=3(x-5)` `:. 2y -10=3x -15` `:. 3x-2y-5=0` Hence, The equation of line is `3x-2y-5=0`
|
|
|
|
|