1. Solve linear equations x+y=2 and 2x+3y=4 using Cross Multiplication Method

Solution:
`x+y=2`

and `2x+3y=4`

`x+y-2=0 ->(1)`

`2x+3y-4=0 ->(2)`

Here,
`a_1=1, b_1=1, c_1=-2`

`a_2=2, b_2=3, c_2=-4`

`x=(b_1*c_2-b_2*c_1)/(a_1*b_2-a_2*b_1)`

`=((1)(-4)-(3)(-2))/((1)(3)-(2)(1))`

`=((-4)-(-6))/((3)-(2))`

`=(2)/(1)`

`=2`

`y=(c_1*a_2-c_2*a_1)/(a_1*b_2-a_2*b_1)`

`=((-2)(2)-(-4)(1))/((1)(3)-(2)(1))`

`=((-4)-(-4))/((3)-(2))`

`=(0)/(1)`

`=0`

`:.x=2" and "y=0`

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