|
Method and examples
|
Method
|
Find Box and Whisker Plots for ungrouped data
|
Enter Data
|
|
|
|
Standard deviation using Direct method or Assumed mean method
Method
|
|
- `85,96,76,108,85,80,100,85,70,95`
- `3,13,11,15,5,4,2`
- `3,23,13,11,15,5,4,2`
- `69,66,67,69,64,63,65,68,72`
- `4,14,12,16,6,3,1,2,3`
- `73,70,71,73,68,67,69,72,76,71`
- `10,50,30,20,10,20,70,30`
- `21,23,19,17,12,15,15,17,17,19,23,23,21,23,25,25,21,19,19,19`
- `2,3,7,8,8,5,5,3,7,3,1,8,6,7,4,5,6,3,2,4,3,4,9,8,3`
|
|
Decimal Place =
|
|
log(x)/ln(x) Option for Geometric mean =
|
|
|
|
|
Solution
|
Solution provided by AtoZmath.com
|
|
Box and Whisker Plots calculator
|
1. 85,96,76,108,85,80,100,85,70,95
2. 3,13,11,11,5,4,2
3. 3,23,13,11,15,3,5,4,2
4. 69,66,67,69,64,63,65,68,72
5. 4,14,12,16,6,3,1,2,3
6. 73,70,71,73,68,67,69,72,76,71
7. 10,50,30,20,10,20,70,30
|
Example1. Calculate Box and Whisker Plots from the following data `10,50,30,20,10,20,70,30`Solution:Box and Whisker Plots :`10,50,30,20,10,20,70,30` Steps of Five-Number Summary Step-1: Arrange the numbers in ascending order`10,10,20,20,30,30,50,70` Step-2: Find the minimum valueMinimum `=10` (the smallest number) Step-3: Find the maximum valueMaximum `=70` (the largest number) Step-4: Find the medianThe median is the middle number in a sorted data set and N is the total number of elements If N is odd then the median is a single middle number, and if N is even then the median is the average of the two middle numbers. `10,10,20,20,30,30,50,70` `N=8` is even, so median is the average of the two middle numbers at position 4 and 5 We have `(20+30)/2=25` `:.` Median `=25` Step-5: Place parentheses around the numbers above and below the median.`{10,10,20,20},{30,30,50,70}` Step-6: Find `Q_1` by finding the median for lower half of data(left of the median)`10,10,20,20` `N=4` is even, so median is the average of the two middle numbers at position 2 and 3 We have `(10+20)/2=15` `:.Q_1=15` Step-7: Find `Q_3` by finding the median for upper half of data(right of the median)`30,30,50,70` `N=4` is even, so median is the average of the two middle numbers at position 2 and 3 We have `(30+50)/2=40` `:.Q_3=40` Step-8: Summary found in the above steps.Minimum `=10` `Q_1=15` Median `=25` `Q_3=40` Maximum `=70`
|
|
|
|
|
|