1. Find Vector projection
`A=(3,4,0)`, `B=(2,2,1)`

Solution:
Here `vec A=(3,4,0),vec B=(2,2,1)`

The Vector projection of `vec A` onto `vec B`

`proj_(vec B)vec A=(vec A * vec B)/|vec B|^2 * vec B`

1. Calculate dot product
`vec A * vec B`

`=A_1*B_1+A_2*B_2+A_3*B_3`

`=3*2+4*2+0*1`

`=6+8`

`=14`

2. Calculate magnitude
`|vec B|`

`=sqrt(B_1^2 + B_2^2 + B_3^2)`

`=sqrt(2^2 + 2^2 + 1^2)`

`=sqrt(4 + 4 + 1)`

`=sqrt(9)`

`=3`


`:.|vec B|^2=9`

The Vector projection is given by
`proj_(vec B)vec A=(vec A * vec B)/|vec B|^2 * vec B`

`=(14)/(9) * vec B`

`=(14)/(9) * (2,2,1)`

`=(28/9,28/9,14/9)`

The scalar projection is given by
`proj_(vec B)vec A=(vec A * vec B)/|vec B|`

Now, `(vec A * vec B)/(|vec B|)`

`=14/3`