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Method and examples
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Arithmetic Progression |
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Problem 4 of 19 |
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4. For arithemetic progression S( ) = , then find f( ).
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Solution
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Solution provided by AtoZmath.com
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This is demo example. Please click on Find button and solution will be displayed in Solution tab (step by step)
| Arithmetic Progression |
4. For arithemetic progression S( 33 ) = 198 , then find f( 17 ).
We have given `S_33 = 198` and we have to find `f(17) = ?`
We know that, `S_n = n/2 [2a + (n - 1)d]`
`S_33 = 33/2 [2a + (33 - 1)d] = 198`
`=> 33 [a + 16d] = 198`
`=> a + 16d = 6 ->(1)`
We know that, `f(n) = a + (n - 1)d`
`f(17) = a + (17 - 1)d`
`=> f(17) = a + 16d`
`=> f(17) = 6` (Using (1))
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