Method and examples
Arithmetic Progression
Problem 8 of 19

8. For arithemetic progression addition of first terms is and addition of first terms is , then find addition of first terms.
 
 
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Arithmetic Progression
8. For arithemetic progression addition of first 17 terms is 24 and addition of first 24 terms is 17 , then find addition of first 41 terms.

We know that, S_n = n/2 [2a + (n - 1)d]

S_17 = 17/2 * [2a + (17 - 1)d] = 24

=> 17/2 * [2a + 16d] = 24

=> 2a + 16 d = 2.8235 ->(1)


We know that, S_n = n/2 [2a + (n - 1)d]

S_24 = 24/2 * [2a + (24 - 1)d] = 17

=> 24/2 * [a + 23d] = 17

=> 2a + 23d = 1.4167 ->(2)

Solving 7 d = -1.4069

=> d = -0.201

From (1) => 2a + 16d = 2.8235

=> 2a = 2.8235 - 16d

=> 2a = 2.8235 - 16 × -0.201

=> 2a = 2.8235 - -3.2157

=> 2a = 6.0392

=> a = 3.0196

We know that, S_n = n/2 [2a + (n - 1)d]

:. S_41 = 41/2 * [2(3.0196) + (41 - 1)(-0.201)]

= 41/2 * [6.0392 + (-8.0392)]

= 41/2 × -2

= -41





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