1. Find Inverse of matrix
A=[311-121111]Solution:=3×(2×1-1×1)-1×(-1×1-1×1)+1×(-1×1-2×1)=3×(2-1)-1×(-1-1)+1×(-1-2)=3×(1)--1×(-2)+1×(-3)=3+2-3=2 = | | +(2×1-1×1) | -(-1×1-1×1) | +(-1×1-2×1) | | | -(1×1-1×1) | +(3×1-1×1) | -(3×1-1×1) | | | +(1×1-1×2) | -(3×1-1×(-1)) | +(3×2-1×(-1)) | |
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= | | +(2-1) | -(-1-1) | +(-1-2) | | | -(1-1) | +(3-1) | -(3-1) | | | +(1-2) | -(3+1) | +(6+1) | |
| T |
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Now, A-1=1|A|×Adj(A)
This material is intended as a summary. Use your textbook for detail explanation.
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