5. Example-2 : `y'=-2x-y`
Find y(0.4) for `y''=xz^2-y^2`, `x_0=0, y_0=1, z_0=0`, with step length 0.2 using Runge-Kutta 2 method (second order differential equation) Solution:Given `y^('')=xz^2-y^2, y(0)=1, y'(0)=0, h=0.2, y(0.4)=?` put `(dy)/(dx)=z` and differentiate w.r.t. x, we obtain `(d^2y)/(dx^2)=(dz)/(dx)` We have system of equations `(dy)/(dx)=z=f(x,y,z)` `(dz)/(dx)=xz^2-y^2=g(x,y,z)` Method-1 : Using formula `k_2=f(x_0+h,y_0+hk_1,z_0+hl_1)`Second order Runge-Kutta (RK2) method for second order differential equation formula `k_1=f(x_n,y_n,z_n)` `l_1=g(x_n,y_n,z_n)` `k_2=f(x_n+h,y_n+hk_1,z_n+hl_1)` `l_2=g(x_n+h,y_n+hk_1,z_n+hl_1)` `y_(n+1)=y_n+(h(k_1+k_2))/2` `z_(n+1)=z_n+(h(l_1+l_2))/2`
for `n=0,x_0=0,y_0=1,z_0=0` `k_1=f(x_0,y_0,z_0)` `=f(0,1,0)` `=0` `l_1=g(x_0,y_0,z_0)` `=g(0,1,0)` `=-1` `k_2=f(x_0+h,y_0+hk_1,z_0+hl_1)` `=f(0.2,1,-0.2)` `=-0.2` `l_2=g(x_0+h,y_0+hk_1,z_0+hl_1)` `=g(0.2,1,-0.2)` `=-0.992` `y_1=y_0+(h(k_1+k_2))/2` `=1-0.02` `=0.98` `z_1=z_0+(h(l_1+l_2))/2` `=0-0.1992` `=-0.1992` `x_1=x_0+h=0+0.2=0.2`
for `n=1,x_1=0.2,y_1=0.98,z_1=-0.1992` `k_1=f(x_1,y_1,z_1)` `=f(0.2,0.98,-0.1992)` `=-0.1992` `l_1=g(x_1,y_1,z_1)` `=g(0.2,0.98,-0.1992)` `=-0.9525` `k_2=f(x_1+h,y_1+hk_1,z_1+hl_1)` `=f(0.4,0.9402,-0.3897)` `=-0.3897` `l_2=g(x_1+h,y_1+hk_1,z_1+hl_1)` `=g(0.4,0.9402,-0.3897)` `=-0.8232` `y_2=y_1+(h(k_1+k_2))/2` `=0.98-0.0589` `=0.9211` `x_2=x_1+h=0.2+0.2=0.4` `:.y(0.4)=0.9211` | `n` | `x_n` | `y_n` | `z_n` | `k_1` | `l_1` | `k_2` | `l_2` | `x_(n+1)` | `y_(n+1)` | `z_(n+1)` | | 0 | 0 | 1 | 0 | 0 | -1 | -0.2 | -0.992 | 0.2 | 0.98 | -0.1992 | | 1 | 0.2 | 0.98 | -0.1992 | -0.1992 | -0.9525 | -0.3897 | -0.8232 | 0.4 | 0.9211 | |
Method-2 : Using formula `k_2=f(x_0+h/2,y_0+(hk_1)/2,z_0+(hl_1)/2)`Second order Runge-Kutta (RK2) method for second order differential equation formula `k_1=f(x_n,y_n,z_n)` `l_1=g(x_n,y_n,z_n)` `k_2=f(x_n+h/2,y_n+(hk_1)/2,z_n+(hl_1)/2)` `l_2=g(x_n+h/2,y_n+(hk_1)/2,z_n+(hl_1)/2)` `y_(n+1)=y_n+hk_2` `z_(n+1)=z_n+hl_2`
for `n=0,x_0=0,y_0=1,z_0=0` `k_1=f(x_0,y_0,z_0)` `=f(0,1,0)` `=0` `l_1=g(x_0,y_0,z_0)` `=g(0,1,0)` `=-1` `k_2=f(x_0+h/2,y_0+(hk_1)/2,z_0+(hl_1)/2)` `=f(0.1,1,-0.1)` `=-0.1` `l_2=g(x_0+h/2,y_0+(hk_1)/2,z_0+(hl_1)/2)` `=g(0.1,1,-0.1)` `=-0.999` `y_1=y_0+hk_2` `=1-0.02` `=0.98` `z_1=z_0+hl_2` `=0-0.1998` `=-0.1998` `x_1=x_0+h=0+0.2=0.2`
for `n=1,x_1=0.2,y_1=0.98,z_1=-0.1998` `k_1=f(x_1,y_1,z_1)` `=f(0.2,0.98,-0.1998)` `=-0.1998` `l_1=g(x_1,y_1,z_1)` `=g(0.2,0.98,-0.1998)` `=-0.9524` `k_2=f(x_1+h/2,y_1+(hk_1)/2,z_1+(hl_1)/2)` `=f(0.3,0.96,-0.295)` `=-0.295` `l_2=g(x_1+h/2,y_1+(hk_1)/2,z_1+(hl_1)/2)` `=g(0.3,0.96,-0.295)` `=-0.8955` `y_2=y_1+hk_2` `=0.98-0.059` `=0.921` `x_2=x_1+h=0.2+0.2=0.4` `:.y(0.4)=0.921` | `n` | `x_n` | `y_n` | `z_n` | `k_1` | `l_1` | `k_2` | `l_2` | `x_(n+1)` | `y_(n+1)` | `z_(n+1)` | | 0 | 0 | 1 | 0 | 0 | -1 | -0.1 | -0.999 | 0.2 | 0.98 | -0.1998 | | 1 | 0.2 | 0.98 | -0.1998 | -0.1998 | -0.9524 | -0.295 | -0.8955 | 0.4 | 0.921 | |
This material is intended as a summary. Use your textbook for detail explanation. Any bug, improvement, feedback then
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