Step by step solution :
Step-1 :
Set up the problem with long division bracket. Put dividend inside bracket and divisor on outside left.

3	7	9

Step-2 :
3 goes into 7 (2 times). Put a 2 in the next place of quotient and multiply 3 by 2 to get 6.
Subtract 6 from 7 to get remainder `(7-6=1)`.

	2
3	7	9
−	6		= 3 × 2
	1

Step-3 :
Now, bring down 9 from the dividend, to make 19

	2
3	7	9
−	6		= 3 × 2
	1	9

Step-4 :
3 goes into 19 (6 times). Put a 6 in the next place of quotient and multiply 3 by 6 to get 18.
Subtract 18 from 19 to get remainder `(19-18=1)`.

	2	6
3	7	9
−	6		= 3 × 2
	1	9
−	1	8	= 3 × 6
		1

Step by step solution :
Step-1 :
Set up the problem with long division bracket. Put dividend inside bracket and divisor on outside left.

4	2	5	9	6

Step-2 :
4 does not go into 2, So we also use the next digit of the dividend.

4 goes into 25 (6 times). Put a 6 in the next place of quotient and multiply 4 by 6 to get 24.
Subtract 24 from 25 to get remainder `(25-24=1)`.

		6
4	2	5	9	6
−	2	4			= 4 × 6
		1

Step-3 :
Now, bring down 9 from the dividend, to make 19

		6
4	2	5	9	6
−	2	4			= 4 × 6
		1	9

Step-4 :
4 goes into 19 (4 times). Put a 4 in the next place of quotient and multiply 4 by 4 to get 16.
Subtract 16 from 19 to get remainder `(19-16=3)`.

		6	4
4	2	5	9	6
−	2	4			= 4 × 6
		1	9
	−	1	6		= 4 × 4
			3

Step-5 :
Now, bring down 6 from the dividend, to make 36

		6	4
4	2	5	9	6
−	2	4			= 4 × 6
		1	9
	−	1	6		= 4 × 4
			3	6

Step-6 :
4 goes into 36 (9 times). Put a 9 in the next place of quotient and multiply 4 by 9 to get 36.
Subtract 36 from 36 to get remainder `(36-36=0)`.

		6	4	9
4	2	5	9	6
−	2	4			= 4 × 6
		1	9
	−	1	6		= 4 × 4
			3	6
		−	3	6	= 4 × 9
				0