Home > Algebra > Future value > Present value using Compound Interest example

6. Present value using Compound Interest example ( Enter your problem )
  1. Find Future value (FV) Example
  2. Find Present value (C) Example
  3. Find Interest Rate (i) Example
  4. Find Time (n) Example

4. Find Time (n) Example





1. Find Time n = ?
Present value C = 1000, Interest Rate i = 10%, Future value FV = 1331,
Interest compounded = Year (1/year)
for Present value using Compound Interest method


Solution:
`C=1000`

`i=10%=0.1` per year (Interest rate)

`FV=1331` (Future value)

Now, Future value (Compound Interest) formula is
`FV=C*(1+i)^n`

`:.1331=1000*(1+0.1)^n`

`:.(1331)/(1000)=(1.1)^n`

`:.1.33=(1.1)^n`

`:.1.1^n=1.33`

taking natural log on both the sides
`:.ln(1.1^n)=ln(1.33)`

`:.n*ln(1.1)=ln(1.33)`

`:.n=ln(1.33)/ln(1.1)`

`:.n=(0.29)/(0.1)`

`:.n=3` year
2. Find Time n = ?
Present value C = 5000, Interest Rate i = 10%, Future value FV = 6050,
Interest compounded = Year (1/year)
for Present value using Compound Interest method


Solution:
`C=5000`

`i=10%=0.1` per year (Interest rate)

`FV=6050` (Future value)

Now, Future value (Compound Interest) formula is
`FV=C*(1+i)^n`

`:.6050=5000*(1+0.1)^n`

`:.(6050)/(5000)=(1.1)^n`

`:.1.21=(1.1)^n`

`:.1.1^n=1.21`

taking natural log on both the sides
`:.ln(1.1^n)=ln(1.21)`

`:.n*ln(1.1)=ln(1.21)`

`:.n=ln(1.21)/ln(1.1)`

`:.n=(0.19)/(0.1)`

`:.n=2` year




This material is intended as a summary. Use your textbook for detail explanation.
Any bug, improvement, feedback then Submit Here





Share this solution or page with your friends.
 
 
Copyright © 2026. All rights reserved. Terms, Privacy
 
 

.