1. Find Cholesky Decomposition ...
[61555155522555225979]Solution:Cholesky decomposition : A=L⋅LT, Every symmetric positive definite matrix A can be decomposed into a product of a unique lower triangular matrix L and its transpose.
Here matrix is symmetric positive definite, so Cholesky decomposition is possible.
A matrix is positive definite if Determinants of all upper-left sub-matrices are positive.
Test method 2: Determinants of all upper-left sub-matrices are positive. | 6 | 15 | 55 | | | 15 | 55 | 225 | | | 55 | 225 | 979 | |
| =3920 |
Determinants are
6,105,3920Here all determinants are positive, so matrix is positive semi-definite.
Formula
lki=aki-∑i-1j=1lij⋅lkjliilkk=√akk-k-1∑j=1l2kjl11=√a11=√6=2.4495l21=a21l11=152.4495=6.1237l22=√a22-l221=√55-(6.1237)2=√55-37.5=4.1833l31=a31l11=552.4495=22.4537l32=a32-l31×l21l22=225-(22.4537)×(6.1237)4.1833=225-137.54.1833=20.9165l33=√a33-l231-l232=√979-(22.4537)2-(20.9165)2=√979-941.6667=6.1101So L | = | | = | | 2.4495 | 0 | 0 | | | 6.1237 | 4.1833 | 0 | | | 22.4537 | 20.9165 | 6.1101 | |
|
L×LT | = | | 2.4495 | 0 | 0 | | | 6.1237 | 4.1833 | 0 | | | 22.4537 | 20.9165 | 6.1101 | |
| × | | 2.4495 | 6.1237 | 22.4537 | | | 0 | 4.1833 | 20.9165 | | | 0 | 0 | 6.1101 | |
| = | |
Solution is possible.
This material is intended as a summary. Use your textbook for detail explanation.
Any bug, improvement, feedback then