1. (951)16 = (      ?      )8Solution:`(951)_16 = (underline{"         "})_8`
First convert hexadecimal to binary
`(951)_16 = (underline{"         "})_2``:. (951)_16 = (underline{100101010001})_2`
Now convert binary to octal
`(100101010001)_2 = (underline{"         "})_8``:. (100101010001)_2 = (underline{4521})_8`
`:. (951)_16 = (underline{4521})_8`
2. (FC3A)16 = (      ?      )8Solution:`(FC3A)_16 = (underline{"         "})_8`
First convert hexadecimal to binary
`(FC3A)_16 = (underline{"         "})_2`| F |  C |  3 |  A |  
| 1111 |  1100 |  0011 |  1010 |  
`:. (FC3A)_16 = (underline{1111110000111010})_2`
Now convert binary to octal
`(1111110000111010)_2 = (underline{"         "})_8`| 001 |  111 |  110 |  000 |  111 |  010 |  
| 1 |  7 |  6 |  0 |  7 |  2 |  
`:. (1111110000111010)_2 = (underline{176072})_8`
`:. (FC3A)_16 = (underline{176072})_8`
This material is intended as a summary. Use your textbook for detail explanation.
Any bug, improvement, feedback then