1. (951)16 = ( ? )8Solution:`(951)_16 = (underline{" "})_8`
First convert hexadecimal to binary
`(951)_16 = (underline{" "})_2``:. (951)_16 = (underline{100101010001})_2`
Now convert binary to octal
`(100101010001)_2 = (underline{" "})_8``:. (100101010001)_2 = (underline{4521})_8`
`:. (951)_16 = (underline{4521})_8`
2. (FC3A)16 = ( ? )8Solution:`(FC3A)_16 = (underline{" "})_8`
First convert hexadecimal to binary
`(FC3A)_16 = (underline{" "})_2`F | C | 3 | A |
1111 | 1100 | 0011 | 1010 |
`:. (FC3A)_16 = (underline{1111110000111010})_2`
Now convert binary to octal
`(1111110000111010)_2 = (underline{" "})_8`001 | 111 | 110 | 000 | 111 | 010 |
1 | 7 | 6 | 0 | 7 | 2 |
`:. (1111110000111010)_2 = (underline{176072})_8`
`:. (FC3A)_16 = (underline{176072})_8`
This material is intended as a summary. Use your textbook for detail explanation.
Any bug, improvement, feedback then