6 base Division Example ( Enter your problem )
  1. Addition
  2. Subtraction
  3. Multiplication
  4. Division
Other related methods
  1. Addition, Subtraction, Multiplication, Division of two Decimal numbers
  2. Addition, Subtraction, Multiplication, Division of two Binary numbers
  3. Addition, Subtraction, Multiplication, Division of two Octal numbers
  4. Addition, Subtraction, Multiplication, Division of two Hexadecimal numbers
  5. Addition, Subtraction, Multiplication, Division of two any base numbers

3. Multiplication
(Previous example)

4. 6 base Division





1. Find division of `(123)_6` and `(4)_6`

Solution:

Solution is
  20
4123
12 =4 × 2
  3
  0=4 × 0
  3

`:.` 123 `-:` 4= 20 Remainder 3
4 table
4×1=4
4×2=12
4×3=20
4×4=24
4×5=32
4×10=40




Step by step solution

Step by step solution :
Step-1 :
Set up the problem with long division bracket. Put dividend inside bracket and divisor on outside left.
    
4123

Step-2 :
4 goes into 12 (2-times). Put a 2 in the next place of quotient and multiply 4 by 2 to get 12.
Subtract 12 from 12 to get remainder `(12-12=0)`.


  2 
4123
12 =4 × 2
  0 

Step-3 :
Now, bring down 3 from the dividend, to make 3
  2 
4123
12 =4 × 2
  3

Step-4 :
4 goes into 3 (0-times). Put a 0 in the next place of quotient and multiply 4 by 0 to get 0.
Subtract 0 from 3 to get remainder `(3-0=3)`.


  20
4123
12 =4 × 2
  3
  0=4 × 0
  3


2. Find division of `(241)_6` and `(2)_6`

Solution:

Solution is
 120
2241
2  =2 × 1
  4 
 4 =2 × 2
  1
  0=2 × 0
  1

`:.` 241 `-:` 2=120 Remainder 1
2 table
2×1=2
2×2=4
2×3=10
2×4=12
2×5=14
2×10=20




Step by step solution

Step by step solution :
Step-1 :
Set up the problem with long division bracket. Put dividend inside bracket and divisor on outside left.
    
2241

Step-2 :
2 goes into 2 (1-times). Put a 1 in the next place of quotient and multiply 2 by 1 to get 2.
Subtract 2 from 2 to get remainder `(2-2=0)`.


 1  
2241
2  =2 × 1
 0  

Step-3 :
Now, bring down 4 from the dividend, to make 4
 1  
2241
2  =2 × 1
  4 

Step-4 :
2 goes into 4 (2-times). Put a 2 in the next place of quotient and multiply 2 by 2 to get 4.
Subtract 4 from 4 to get remainder `(4-4=0)`.


 12 
2241
2  =2 × 1
  4 
 4 =2 × 2
  0 

Step-5 :
Now, bring down 1 from the dividend, to make 1
 12 
2241
2  =2 × 1
  4 
 4 =2 × 2
  1

Step-6 :
2 goes into 1 (0-times). Put a 0 in the next place of quotient and multiply 2 by 0 to get 0.
Subtract 0 from 1 to get remainder `(1-0=1)`.


 120
2241
2  =2 × 1
  4 
 4 =2 × 2
  1
  0=2 × 0
  1


3. Find division of `(31021)_6` and `(5)_6`

Solution:

Solution is
  3451
531021
23   =5 × 3
  40  
 32  =5 × 4
  42 
  41 =5 × 5
  11
  5=5 × 1
  2

`:.` 31021 `-:` 5= 3451 Remainder 2
5 table
5×1=5
5×2=14
5×3=23
5×4=32
5×5=41
5×10=50




Step by step solution

Step by step solution :
Step-1 :
Set up the problem with long division bracket. Put dividend inside bracket and divisor on outside left.
      
531021

Step-2 :
5 goes into 31 (3-times). Put a 3 in the next place of quotient and multiply 5 by 3 to get 23.
Subtract 23 from 31 to get remainder `(31-23=4)`.


  3   
531021
23   =5 × 3
  4   

Step-3 :
Now, bring down 0 from the dividend, to make 40
  3   
531021
23   =5 × 3
  40  

Step-4 :
5 goes into 40 (4-times). Put a 4 in the next place of quotient and multiply 5 by 4 to get 32.
Subtract 32 from 40 to get remainder `(40-32=4)`.


  34  
531021
23   =5 × 3
  40  
 32  =5 × 4
  4  

Step-5 :
Now, bring down 2 from the dividend, to make 42
  34  
531021
23   =5 × 3
  40  
 32  =5 × 4
  42 

Step-6 :
5 goes into 42 (5-times). Put a 5 in the next place of quotient and multiply 5 by 5 to get 41.
Subtract 41 from 42 to get remainder `(42-41=1)`.


  345 
531021
23   =5 × 3
  40  
 32  =5 × 4
  42 
  41 =5 × 5
  1 

Step-7 :
Now, bring down 1 from the dividend, to make 11
  345 
531021
23   =5 × 3
  40  
 32  =5 × 4
  42 
  41 =5 × 5
  11

Step-8 :
5 goes into 11 (1-times). Put a 1 in the next place of quotient and multiply 5 by 1 to get 5.
Subtract 5 from 11 to get remainder `(11-5=2)`.


  3451
531021
23   =5 × 3
  40  
 32  =5 × 4
  42 
  41 =5 × 5
  11
  5=5 × 1
  2



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3. Multiplication
(Previous example)






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