2. Find Subtraction of B06 and C7C using 15's complement

Solution:

15's complement subtraction steps :

1. At first, find 15's complement of the B(subtrahend).
2. Then add it to the A(minuend).
3. If the final carry over of the sum is 1, then it is dropped and 1 is added to the result.
4. If there is no carry over, then 15's complement of the sum is the final result and it is negative.

Here A = B06, B = C7C.
Find A - B = ? using 15's complement
First find 15's complement of B = C7C


Step-1: 15's complement of C7C is obtained by subtracting each digit from F

	F	F	F
-	C	7	C
	3	8	3

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Step-2: Now Add this 383 to B06

	B	0	6
+	3	8	3
	E	8	9

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Step by step solution of B06 + 383 = E89

Write the numbers, so that each digit lines up vertically

	B	0	6
+	3	8	3

Step-1 :
`=6_16+3_16`
`=6_10+3_10`
`=9_10`
`=9_16`
Write the 9 in the sum place

	B	0	6
+	3	8	3
			9

Step-2 :
`=0_16+8_16`
`=0_10+8_10`
`=8_10`
`=8_16`
Write the 8 in the sum place

	B	0	6
+	3	8	3
		8	9

Step-3 :
`=B_16+3_16`
`=11_10+3_10`
`=14_10`
`=E_16`
Write the E in the sum place

	B	0	6
+	3	8	3
	E	8	9

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Here there is no carry, answer is - (15's complement of the sum obtained E89)


Step-1: 15's complement of E89 is obtained by subtracting each digit from F

	F	F	F
-	E	8	9
	1	7	6

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So answer is -176

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