2. Find Subtraction of B06 and C7C using 16's complement

Solution:

16's complement subtraction steps :

1. At first, find 16's complement of the B(subtrahend).
2. Then add it to the A(minuend).
3. If the final carry over of the sum is 1, then it is dropped and the result is positive.
4. If there is no carry over, then 16's complement of the sum is the final result and it is negative.

Here A = B06, B = C7C.
Find A - B = ? using 16's complement
First find 16's complement of B = C7C


Step-1: 15's complement of C7C is obtained by subtracting each digit from F

	F	F	F
-	C	7	C
	3	8	3

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Step-2: Now add 1 :
383 + 1 = 384

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Step-3: Now Add this 384 to B06

	B	0	6
+	3	8	4
	E	8	A

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Step by step solution of B06 + 384 = E8A

Write the numbers, so that each digit lines up vertically

	B	0	6
+	3	8	4

Step-1 :
`=6_16+4_16`
`=6_10+4_10`
`=10_10`
`=A_16`
Write the A in the sum place

	B	0	6
+	3	8	4
			A

Step-2 :
`=0_16+8_16`
`=0_10+8_10`
`=8_10`
`=8_16`
Write the 8 in the sum place

	B	0	6
+	3	8	4
		8	A

Step-3 :
`=B_16+3_16`
`=11_10+3_10`
`=14_10`
`=E_16`
Write the E in the sum place

	B	0	6
+	3	8	4
	E	8	A

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Here there is no carry, answer is - (16's complement of the sum obtained E8A)


Step-1: 15's complement of E8A is obtained by subtracting each digit from F

	F	F	F
-	E	8	A
	1	7	5

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Step-2: Now add 1 :
175 + 1 = 176

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So answer is -176

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