1) 2 unbiased coins are tossed. What is the probability of getting atleast 1 Head
Solution:
Total number of outcomes possible when a coin is tossed`=2`
Hence, total number of outcomes possible when `2` coins are tossed,
`:.n(S)=2 xx 2=4`
Here `S` = {HH, HT, TH, TT}
Let `E` = event of getting atleast `1` head
`:.` `E` = {HH, HT, TH}
`:.n(E) = 3`
`:.P(E)=(n(E))/(n(S))=3/4`
2) 2 unbiased coins are tossed. What is the probability of getting exactly 2 Head
Solution:
Total number of outcomes possible when a coin is tossed`=2`
Hence, total number of outcomes possible when `2` coins are tossed,
`:.n(S)=2 xx 2=4`
Here `S` = {HH, HT, TH, TT}
Let `E` = event of getting exactly `2` head
`:.` `E` = {HH}
`:.n(E) = 1`
`:.P(E)=(n(E))/(n(S))=1/4`
3) 2 unbiased coins are tossed. What is the probability of getting atleast 1 Tail
Solution:
Total number of outcomes possible when a coin is tossed`=2`
Hence, total number of outcomes possible when `2` coins are tossed,
`:.n(S)=2 xx 2=4`
Here `S` = {HH, HT, TH, TT}
Let `E` = event of getting atleast `1` tail
`:.` `E` = {HT, TH, TT}
`:.n(E) = 3`
`:.P(E)=(n(E))/(n(S))=3/4`
4) 2 unbiased coins are tossed. What is the probability of getting exactly 2 Tail
Solution:
Total number of outcomes possible when a coin is tossed`=2`
Hence, total number of outcomes possible when `2` coins are tossed,
`:.n(S)=2 xx 2=4`
Here `S` = {HH, HT, TH, TT}
Let `E` = event of getting exactly `2` tail
`:.` `E` = {TT}
`:.n(E) = 1`
`:.P(E)=(n(E))/(n(S))=1/4`
This material is intended as a summary. Use your textbook for detail explanation.
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