1) 1 card is drawn, what is the probability that, 1 FACE Card card is CLUB .
Solution:
Total number of ways of drawing 1 cards from 52 cards
`n(S) = 52`
Let `E` = event of getting 1 card is face card of club
Total number of face card of club cards = 4
Hence, `n(E)=` number of ways of drawing 1 face card of club from 4
`n(E) = 4`
`:.P(E)=(n(E))/(n(S))=4/52=1/13`
2) 1 card is drawn, what is the probability that, 1 QUEEN card is CLUB or 1 KING card is HEART
Solution:
Total number of ways of drawing 1 cards from 52 cards
`n(S) = 52`
Let `E` = event of getting 1 card is queen of club or king of heart
Total number of queen of club cards = 1
Total number of king of heart cards = 1
Hence, `n(E)=` number of ways of drawing 1 queen of club from 1 or 1 king of heart from 1
`:. n(E)={::}^1 C_1+{::}^1 C_1=1+1=2`
`:.P(E)=(n(E))/(n(S))=2/52=1/26`
3) 2 card is drawn, what is the probability that, 1 QUEEN card is CLUB and 1 KING card is HEART
Solution:
Total number of ways of drawing 2 cards from 52 cards
`n(S) = {::}^52 C_2=1326`
Let `E` = event of getting 1 card is queen of club and 1 card is king of heart
Total number of queen of club cards = 1
Total number of king of heart cards = 1
Hence, `n(E)=` number of ways of drawing 1 queen of club from 1 or 1 king of heart from 1
`:. n(E)={::}^1 C_1xx{::}^1 C_1=1 xx 1=1`
`:.P(E)=(n(E))/(n(S))=1/1326`
4) 2 card is drawn, what is the probability that, 2 QUEEN card is RED or 2 KING card is BLACK
Solution:
Total number of ways of drawing 2 cards from 52 cards
`n(S) = {::}^52 C_2=1326`
Let `E` = event of getting 2 card is queen of red or 2 card is king of black
Total number of queen of red cards = 2
Total number of king of black cards = 2
Hence, `n(E)=` number of ways of drawing 2 queen of red from 2 or 2 king of black from 2
`:. n(E)={::}^2 C_2+{::}^2 C_2=1+1=2`
`:.P(E)=(n(E))/(n(S))=2/1326=1/663`
5) 2 card is drawn, what is the probability that, 2 QUEEN card is BLACK .
Solution:
Total number of ways of drawing 2 cards from 52 cards
`n(S) = {::}^52 C_2=1326`
Let `E` = event of getting 2 card is queen of black
Total number of queen of black cards = 2
Hence, `n(E)=` number of ways of drawing 2 queen of black from 2
`n(E) = {::}^2 C_2=1`
`:.P(E)=(n(E))/(n(S))=1/1326`
6) 2 card is drawn, what is the probability that, 2 QUEEN card is RED .
Solution:
Total number of ways of drawing 2 cards from 52 cards
`n(S) = {::}^52 C_2=1326`
Let `E` = event of getting 2 card is queen of red
Total number of queen of red cards = 2
Hence, `n(E)=` number of ways of drawing 2 queen of red from 2
`n(E) = {::}^2 C_2=1`
`:.P(E)=(n(E))/(n(S))=1/1326`
This material is intended as a summary. Use your textbook for detail explanation.
Any bug, improvement, feedback then
