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Method and examples
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HCF_LCM |
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Problem 4 of 11 |
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4. Find the least number which when divided by leaves the same remainder in each case.
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Solution
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Solution provided by AtoZmath.com
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This is demo example. Please click on Find button and solution will be displayed in Solution tab (step by step)
| HCF_LCM |
4. Find the least number which when divided by 6,7, 8, 9,12 leaves the same remainder 2 in each case.
`"Required number" = ( "LCM of " 6,7,8,9,12 ) + 2 = 504 + 2 = 506`.
| 2 | 6 | | 7 | | 8 | | 9 | | 12 | | 2 | 3 | | 7 | | 4 | | 9 | | 6 | | 2 | 3 | | 7 | | 2 | | 9 | | 3 | | 3 | 3 | | 7 | | 1 | | 9 | | 3 | | 3 | 1 | | 7 | | 1 | | 3 | | 1 | | 7 | 1 | | 7 | | 1 | | 1 | | 1 | | | 1 | | 1 | | 1 | | 1 | | 1 |
LCM of 6,7,8,9,12 = 2 × 2 × 2 × 3 × 3 × 7 = 504
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