|
|
|
|
|
|
|
|
|
Method and examples
|
|
|
|
HCF_LCM |
|
|
|
|
|
|
Problem 8 of 11 |
|
|
|
8. The greatest number that will divide , , leaving respectively , , as remainder.
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
Solution
|
Solution provided by AtoZmath.com
|
|
|
This is demo example. Please click on Find button and solution will be displayed in Solution tab (step by step)
| HCF_LCM |
8. The greatest number that will divide 290 , 460 , 552 leaving respectively 4 , 5 , 6 as remainder.
The number divides 290 and leaves 4 as remainder
`:.` The number exactly divides 290 - 4 = 286
The number divides 460 and leaves 5 as remainder
`:.` The number exactly divides 460 - 5 = 455
The number divides 552 and leaves 6 as remainder
`:.` The number exactly divides 552 - 6 = 546
Now, we have to find HCF of `286, 455, 546`
Find HCF of (286,455)
| | | | | | |
| | 286 | | | | | | | | | | | | | | |
| |
| | | | | | | | | | | | | | | | | | | | | |
| |
| | | | | | | | | | | | | | | | | | | | | | | | | | |
| |
| | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | |
| |
| | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | |
| | | | | | | | | | | | |
HCF of (286, 455) = 13
Now find HCF of (13,546)
HCF of (13, 546) = 13
`:.` HCF of given numbers (286,455,546) = 13
`:.` Required number = HCF of `286, 455, 546 = 13`.
|
|
|
|
|
|
|
Share this solution or page with your friends.
|
|
|
|
