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Spearman's Rank Correlation Coefficient (RHO) example ( Enter your problem )
  1. Rank correlation coefficient for marks given by 2 judge example
  2. Rank correlation coefficient for rank given by 2 judge example
  3. Rank correlation coefficient for rank given by 3 judge example

2. Rank correlation coefficient for rank given by 2 judge example
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1. Rank correlation coefficient for marks given by 2 judge example





Formula
1. `r = 1 - (6 * sum d^2)/(n(n^2 - 1))`

Examples
1. Calculate Spearman's Rank Correlation Coefficient from the following Data
X35404243405354494155
Y10210197983810197929595


Solution:
`x``y``Rx``Ry``d=Rx-Ry``d^2`
35102101981
401018.52.5636
429765.50.50.25
43985411
40388.510-1.52.25
5310132.50.50.25
549725.5-3.512.25
499249-525
419577.5-0.50.25
559517.5-6.542.25
------------------
----------200.5


`r = 1 - (6 * sum d^2)/(n(n^2 - 1))`

`=1 - (6 * 200.5)/(10 * (10^2 - 1))`

`=1 - (6 * 200.5)/(10 * (100 - 1))`

`=1 - 1203/990`

`=1 - 1.22`

`=-0.22`
2. Calculate Spearman's Rank Correlation Coefficient from the following Data
X4243405354494155
Y97983810197929595


Solution:
`x``y``Rx``Ry``d=Rx-Ry``d^2`
429763.52.56.25
43985239
40388800
531013124
549723.5-1.52.25
499247-39
419575.51.52.25
559515.5-4.520.25
------------------
----------53


`r = 1 - (6 * sum d^2)/(n(n^2 - 1))`

`=1 - (6 * 53)/(8 * (8^2 - 1))`

`=1 - (6 * 53)/(8 * (64 - 1))`

`=1 - 318/504`

`=1 - 0.631`

`=0.369`


This material is intended as a summary. Use your textbook for detail explanation.
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