1. Distance, Slope of two points example ( Enter your problem )
  1. Find the distance between the points A(5,-8) and B(-7,-3)
  2. Find the slope of the line joining points A(4,-8) and B(5,-2)
  3. If distance between the points (5,3) and (x,-1) is 5, then find the value of x
  4. If slope of the line joining points A(x,0), B(-3,-2) is 2/7, find the value of x
Other related methods
  1. Distance, Slope of two points
  2. Points are Collinear or Triangle or Quadrilateral form
  3. Find Ratio of line joining AB and is divided by P
  4. Find Midpoint or Trisection points or equidistant points on X-Y axis
  5. Find Centroid, Circumcenter, Area of a triangle
  6. Find the equation of a line using slope, point, X-intercept, Y-intercept
  7. Find Slope, X-intercept, Y-intercept of a line
  8. Find the equation of a line passing through point of intersection of two lines and slope or a point
  9. Find the equation of a line passing through a point and parallel or perpendicular to Line-2 or point-2 and point-3
  10. Find the equation of a line passing through point of intersection of Line-1, Line-2 and parallel or perpendicular to Line-3
  11. For two lines, find Angle, intersection point and determine if parallel or perpendicular lines
  12. Reflection of points about x-axis, y-axis, origin

3. If distance between the points (5,3) and (x,-1) is 5, then find the value of x
(Previous example)
2. Points are Collinear or Triangle or Quadrilateral form
(Next method)

4. If slope of the line joining points A(x,0), B(-3,-2) is 2/7, find the value of x





1. If slope of the line joining points `A(x,0), B(-3,-2)` is `2/7`, find the value of `x`

Solution:
Points are `(x,0),(-3,-2)` and Slope `=2/7`

`:. x_1=x,y_1=0,x_2=-3,y_2=-2,m=2/7`

Slope `=m=(y_2-y_1)/(x_2-x_1)`

`:. 2/7=(-2)/(-3-x)`

`:. 2/7*(-3-x)=-2`

`:. -3-x=-2*7/2`

`:. -3-x=-7`

`:. x=-3+7`

`:. x=4`

2. If slope of the line joining points `A(2,x), B(-3,7)` is `1`, find the value of `x`

Solution:
Points are `(2,x),(-3,7)` and Slope `=1`

`:. x_1=2,y_1=x,x_2=-3,y_2=7,m=1`

Slope `=m=(y_2-y_1)/(x_2-x_1)`

`:. 1=(7-x)/(-3-2)`

`:. 1=(7-x)/(-5)`

`:. 1*-5=7-x`

`:. -5=7-x`

`:. x=7+5`

`:. x=12`

3. If slope of the line joining points `A(x,5), B(-1,2)` is `3/4`, find the value of `x`

Solution:
Points are `(x,5),(-1,2)` and Slope `=3/4`

`:. x_1=x,y_1=5,x_2=-1,y_2=2,m=3/4`

Slope `=m=(y_2-y_1)/(x_2-x_1)`

`:. 3/4=(2-5)/(-1-x)`

`:. 3/4*(-1-x)=-3`

`:. -1-x=-3*4/3`

`:. -1-x=-4`

`:. x=-1+4`

`:. x=3`

4. If slope of the line joining points `A(2,5), B(x,3)` is `2`, find the value of `x`

Solution:
Points are `(2,5),(x,3)` and Slope `=2`

`:. x_1=2,y_1=5,x_2=x,y_2=3,m=2`

Slope `m = (y_2-y_1)/(x_2-x_1)`

`:. 2=(3-5)/(x-2)`

`:. 2=(-2)/(x-2)`

`:. 2*(x-2)=-2`

`:. x-2=-2/2`

`:. x=-1+2`

`:. x=1`

5. If slope of the line joining points `A(x,2), B(6,-8)` is `-5/4`, find the value of `x`

Solution:
Points are `(x,2),(6,-8)` and Slope `=-5/4`

`:. x_1=x,y_1=2,x_2=6,y_2=-8,m=-5/4`

Slope `=m=(y_2-y_1)/(x_2-x_1)`

`:. -5/4=(-8-2)/(6-x)`

`:. -5/4*(6-x)=-10`

`:. 6-x=-10*-4/5`

`:. 6-x=8`

`:. x=6-8`

`:. x=-2`

6. If slope of the line joining points `A(-2,x), B(5,-7)` is `-1`, find the value of `x`

Solution:
Points are `(-2,x),(5,-7)` and Slope `=-1`

`:. x_1=-2,y_1=x,x_2=5,y_2=-7,m=-1`

Slope `=m=(y_2-y_1)/(x_2-x_1)`

`:. -1=(-7-x)/(5+2)`

`:. -1=(-7-x)/(7)`

`:. -1*7=-7-x`

`:. -7=-7-x`

`:. x=-7+7`

`:. x=0`

7. If slope of the line joining points `A(2,3), B(x,6)` is `3/5`, find the value of `x`

Solution:
Points are `(2,3),(x,6)` and Slope `=3/5`

`:. x_1=2,y_1=3,x_2=x,y_2=6,m=3/5`

Slope `m = (y_2-y_1)/(x_2-x_1)`

`:. 3/5=(6-3)/(x-2)`

`:. 3/5=(3)/(x-2)`

`:. 3/5*(x-2)=3`

`:. x-2=3*5/3`

`:. x=5+2`

`:. x=7`

8. If slope of the line joining points `A(-3,4), B(5,x)` is `-5/4`, find the value of `x`

Solution:
Points are `(-3,4),(5,x)` and Slope `=-5/4`

`:. x_1=-3,y_1=4,x_2=5,y_2=x,m=-5/4`

Slope `=m=(y_2-y_1)/(x_2-x_1)`

`:. -5/4=(x-4)/(5+3)`

`:. -5/4=(x-4)/8`

`:. -5/4*8=x-4`

`:. x-4=-10`

`:. x=-10+4`

`:. x=-6`

9. If slope of the line joining points `A(0,x), B(5,-2)` is `-9/5`, find the value of `x`

Solution:
Points are `(0,x),(5,-2)` and Slope `=-9/5`

`:. x_1=0,y_1=x,x_2=5,y_2=-2,m=-9/5`

Slope `=m=(y_2-y_1)/(x_2-x_1)`

`:. -9/5=(-2-x)/(5)`

`:. -9/5*5=-2-x`

`:. -9=-2-x`

`:. x=-2+9`

`:. x=7`


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3. If distance between the points (5,3) and (x,-1) is 5, then find the value of x
(Previous example)
2. Points are Collinear or Triangle or Quadrilateral form
(Next method)





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