`f(x,y)=x^3+x^2y^3-2y^2`
Find Partial derivative, Derivative order = `x`Solution:Now,
`del/(delx)(x^3+x^2y^3-2y^2)`
`=del/(delx)(x^3)+del/(delx)(x^2y^3)-del/(delx)(2y^2)`
`del/(delx)(x^2y^3)=2xy^3+0`
`del/(delx)(x^2y^3)`
`=(del/(delx)(x^2))y^3+x^2(del/(delx)(y^3))`
`del/(delx)(y^3)=0`
`del/(delx)(y^3)`
`=3y^2*del/(delx)(y)`
`=3y^2*0`
`=0`
`=(2x)y^3+x^2*0`
`=2xy^3+0`
`del/(delx)(2y^2)=0`
`del/(delx)(2y^2)`
`=4y*del/(delx)(y)`
`=4y*0`
`=0`
`=3x^2+(2xy^3+0)-0`
`=3x^2+2xy^3+0-0`
`=3x^2+2xy^3`
`:.(del)/(del x)(x^3+x^2y^3-2y^2)=3x^2+2xy^3`
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