`f(x,y)=x^3+x^2y^3-2y^2`
Find Partial derivative, Derivative order = `y`Solution:Now,
`del/(dely)(x^3+x^2y^3-2y^2)`
`=del/(dely)(x^3)+del/(dely)(x^2y^3)-del/(dely)(2y^2)`
`del/(dely)(x^3)=0`
`del/(dely)(x^3)`
`=3x^2*del/(dely)(x)`
`=3x^2*0`
`=0`
`del/(dely)(x^2y^3)=0+3x^2y^2`
`del/(dely)(x^2y^3)`
`=(del/(dely)(x^2))y^3+x^2(del/(dely)(y^3))`
`del/(dely)(x^2)=0`
`del/(dely)(x^2)`
`=2x*del/(dely)(x)`
`=2x*0`
`=0`
`=0y^3+x^2(3y^2)`
`=0+3x^2y^2`
`=0+(0+3x^2y^2)-4y`
`=0+0+3x^2y^2-4y`
`=3x^2y^2-4y`
`:.(del)/(del y)(x^3+x^2y^3-2y^2)=3x^2y^2-4y`
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