1. Solve Equations 2x+5y=21,x+2y=8 using Gauss-Jordan Elimination methodSolution:Total Equations are `2`
`2x+5y=21 -> (1)`
`x+2y=8 -> (2)`
Converting given equations into matrix form
`R_1 larr R_1-:2`
|  =  |  |  `1` `1=2-:2` `R_1 larr R_1-:2` |  `5/2` `5/2=5-:2` `R_1 larr R_1-:2` |  |  `21/2` `21/2=21-:2` `R_1 larr R_1-:2` |  |   | `1` | `2` |  | `8` |  |  
  | 
`R_2 larr R_2- R_1`
|  =  |  | `1` | `5/2` |  | `21/2` |  |   |  `0` `0=1-1` `R_2 larr R_2- R_1` |  `-1/2` `-1/2=2-5/2` `R_2 larr R_2- R_1` |  |  `-5/2` `-5/2=8-21/2` `R_2 larr R_2- R_1` |  |  
  | 
`R_2 larr R_2xx-2`
|  =  |  | `1` | `5/2` |  | `21/2` |  |   |  `0` `0=0xx-2` `R_2 larr R_2xx-2` |  `1` `1=-1/2xx-2` `R_2 larr R_2xx-2` |  |  `5` `5=-5/2xx-2` `R_2 larr R_2xx-2` |  |  
  | 
`R_1 larr R_1-5/2xx R_2`
|  =  |  |  `1` `1=1-5/2xx0` `R_1 larr R_1-5/2xx R_2` |  `0` `0=5/2-5/2xx1` `R_1 larr R_1-5/2xx R_2` |  |  `-2` `-2=21/2-5/2xx5` `R_1 larr R_1-5/2xx R_2` |  |   | `0` | `1` |  | `5` |  |  
  | 
`i.e.`
`x=-2`
`y=5`
Solution By Gauss jordan elimination method.
`x = -2`
`y = 5`
This material is intended as a summary. Use your textbook for detail explanation.
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