Find the approximated integral value using Right Riemann Sum

x	f(x)
0.00	1.0000
0.25	0.9896
0.50	0.9589
0.75	0.9089
1.00	0.8415

Solution:
The value of table for `x` and `f(x)`

`x`	`f(x)`
`x_0=0`	`f(x_(0))=1`
`x_1=0.25`	`f(x_(1))=0.9896`
`x_2=0.5`	`f(x_(2))=0.9589`
`x_3=0.75`	`f(x_(3))=0.9089`
`x_4=1`	`f(x_(4))=0.8415`

Method-1:
Using Right Riemann Sum


`int f(x) dx=Delta x xx(f(x_(1))+f(x_(2))+f(x_(3))+f(x_(4)))`

`=0.25xx(0.9896+0.9589+0.9089+0.8415)`

`=0.25xx(3.6989)`

`=0.9247`

Solution by Right Riemann Sum is `0.9247`

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