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2. Right Riemann Sum example ( Enter your problem )
  1. Formula & Example-1 (table data)
  2. Example-2 (table data)
  3. Example-3 (table data)
  4. Example-4 `(f(x)=1/x)`
  5. Example-5 `(f(x)=1/(x+1))`
  6. Example-6 `(f(x)=x^3-2x+1)`
  7. Example-7 `(f(x)=2x^3-4x+1)`
Other related methods
  1. Left Riemann Sum
  2. Right Riemann Sum
  3. Midpoint Rule of Riemann Sum
  4. Left endpoint approximation
  5. Right endpoint approximation
  6. Trapezoidal rule
  7. Simpson's 1/3 rule
  8. Simpson's 3/8 rule
  9. Boole's rule
  10. Weddle's rule

1. Left Riemann Sum
(Previous method)
2. Example-2 (table data)
(Next example)

1. Formula & Example-1 (table data)





Formula
1. Right Riemann Sum
`int y dx=h (y_1+y_2+ ... + y_n)`
`int f(x) dx=Delta x xx(f(x_(1))+f(x_(2))+...+f(x_(n)))`

Examples
1. Find the approximated integral value using Right Riemann Sum
xf(x)
1.44.0552
1.64.9530
1.86.0436
2.07.3891
2.29.0250


Solution:
The value of table for `x` and `f(x)`

`x``f(x)`
`x_0=1.4``f(x_(0))=4.0552`
`x_1=1.6``f(x_(1))=4.953`
`x_2=1.8``f(x_(2))=6.0436`
`x_3=2``f(x_(3))=7.3891`
`x_4=2.2``f(x_(4))=9.025`


Method-1:
Using Right Riemann Sum
`int f(x) dx=Delta x xx(f(x_(1))+f(x_(2))+...+f(x_(n)))`


`int f(x) dx=Delta x xx(f(x_(1))+f(x_(2))+f(x_(3))+f(x_(4)))`

`=0.2xx(4.953+6.0436+7.3891+9.025)`

`=0.2xx(27.4107)`

`=5.4821`

Solution by Right Riemann Sum is `5.4821`




This material is intended as a summary. Use your textbook for detail explanation.
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1. Left Riemann Sum
(Previous method)
2. Example-2 (table data)
(Next example)





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