Formula
1. Three-point FDF (Forward difference formula)
`f^'(x)=1/(2h)[-3f(x)+4f(x+h)-f(x+2h)]`
|
2. Three-point BDF (Backward difference formula)
`f^'(x)=1/(2h)[f(x-2h)-4f(x-h)+3f(x)]`
|
3. Three-point CDF (Central difference formula)
`f^'(x)=(f(x+h)-f(x-h))/(2h)`
|
|
|
4. Three-point FDF (Forward difference formula) for second derivatives
`f^('')(x)=(f(x)-2f(x+h)+f(x+2h))/(h^2)`
|
5. Three-point BDF (Backward difference formula) for second derivatives
`f^('')(x)=(f(x-2h)-2f(x-h)+f(x))/(h^2)`
|
6. Three-point CDF (Central difference formula) for second derivatives
`f^('')(x)=(f(x-h)-2f(x)+f(x+h))/(h^2)`
|
Examples
1. Using Three point Forward difference, Backward difference, Central difference formula numerical differentiation to find solution
| x | 1 | 1.05 | 1.10 | 1.15 | 1.20 | 1.25 | 1.30 |
| f(x) | 1 | 1.02470 | 1.04881 | 1.07238 | 1.09545 | 1.11803 | 1.14018 |
`f^'(1.10) and f^('')(1.10)`
Solution:
The value of table for `x` and `y`
| x | 1 | 1.05 | 1.1 | 1.15 | 1.2 | 1.25 | 1.3 |
|---|
| y | 1 | 1.0247 | 1.0488 | 1.0724 | 1.0954 | 1.118 | 1.1402 |
|---|
Three-point FDF (Forward difference formula)
`f^'(x)=1/(2h)[-3f(x)+4f(x+h)-f(x+2h)]`
`f^'(1.10)=1/(2*0.05)[-3f(1.10)+4f(1.10+0.05)-f(1.10+2*0.05)]`
`f^'(1.10)=1/0.1[-3f(1.10)+4f(1.15)-f(1.2)]`
`f^'(1.10)=1/0.1[-3(1.0488)+4(1.0724)-1.0954]`
`f^'(1.10)=0.4764`
Three-point BDF (Backward difference formula)
`f^'(x)=1/(2h)[f(x-2h)-4f(x-h)+3f(x)]`
`f^'(1.10)=1/(2*0.05)[f(1.10-2*0.05)-4f(1.10-0.05)+3f(1.10)]`
`f^'(1.10)=1/0.1[f(1)-4f(1.05)+3f(1.10)]`
`f^'(1.10)=1/0.1[1-4(1.0247)+3(1.0488)]`
`f^'(1.10)=0.4763`
Three-point CDF (Central difference formula)
`f^'(x)=(f(x+h)-f(x-h))/(2h)`
`f^'(1.10)=(f(1.10+0.05)-f(1.10-0.05))/(2*0.05)`
`f^'(1.10)=(f(1.15)-f(1.05))/0.1`
`f^'(1.10)=(1.0724-1.0247)/0.1`
`f^'(1.10)=0.4768`
Three-point FDF (Forward difference formula) for second derivatives
`f^('')(x)=(f(x)-2f(x+h)+f(x+2h))/(h^2)`
`f^('')(1.10)=(f(1.10)-2f(1.10+0.05)+f(1.10+2*0.05))/((0.05)^2)`
`f^('')(1.10)=(f(1.10)-2f(1.15)+f(1.2))/(0.0025)`
`f^('')(1.10)=(1.0488-2(1.0724)+1.0954)/(0.0025)`
`f^('')(1.10)=-0.2`
Three-point BDF (Backward difference formula) for second derivatives
`f^('')(x)=(f(x-2h)-2f(x-h)+f(x))/(h^2)`
`f^('')(1.10)=(f(1.10-2*0.05)-2f(1.10-0.05)+f(1.10))/((0.05)^2)`
`f^('')(1.10)=(f(1)-2f(1.05)+f(1.10))/(0.0025)`
`f^('')(1.10)=(1-2(1.0247)+1.0488)/(0.0025)`
`f^('')(1.10)=-0.236`
Three-point CDF (Central difference formula) for second derivatives
`f^('')(x)=(f(x-h)-2f(x)+f(x+h))/(h^2)`
`f^('')(1.10)=(f(1.10-0.05)-2f(1.10)+f(1.10+0.05))/(0.05)^2`
`f^('')(1.10)=(f(1.05)-2f(1.10)+f(1.15))/(0.0025)`
`f^('')(1.10)=(1.0247-2(1.0488)+1.0724)/(0.0025)`
`f^('')(1.10)=-0.216`
This material is intended as a summary. Use your textbook for detail explanation.
Any bug, improvement, feedback then
