`f(x)=cosx` and `h = 0.05`, estimate `f^'(1.2) and f^('')(1.2)`
using Three point Forward difference, Backward difference, Central difference formula numerical differentiation
Also find exact value of f', f'' and error for each estimation

Solution:
Equation is `f(x) = cos(x)`.

`:. f^'(x) = -sin(x)`

`:. f^('')(x) = -cos(x)`

The value of table for `x` and `y`

x	1.1	1.15	1.2	1.25	1.3
y	0.4536	0.4085	0.3624	0.3153	0.2675

Three-point FDF (Forward difference formula)
`f^'(x)=1/(2h)[-3f(x)+4f(x+h)-f(x+2h)]`

`f^'(1.2)=1/(2*0.05)[-3f(1.2)+4f(1.2+0.05)-f(1.2+2*0.05)]`

`f^'(1.2)=1/0.1[-3f(1.2)+4f(1.25)-f(1.3)]`

`f^'(1.2)=1/0.1[-3(0.3624)+4(0.3153)-0.2675]`

`f^'(1.2)=-0.9328`

Absolute Error:`|"exact value of " f^'(1.2)-(-0.9328)|=|-0.932 +0.9328|=0.0008`

---

Three-point BDF (Backward difference formula)
`f^'(x)=1/(2h)[f(x-2h)-4f(x-h)+3f(x)]`

`f^'(1.2)=1/(2*0.05)[f(1.2-2*0.05)-4f(1.2-0.05)+3f(1.2)]`

`f^'(1.2)=1/0.1[f(1.1)-4f(1.15)+3f(1.2)]`

`f^'(1.2)=1/0.1[0.4536-4(0.4085)+3(0.3624)]`

`f^'(1.2)=-0.9328`

Absolute Error:`|"exact value of " f^'(1.2)-(-0.9328)|=|-0.932 +0.9328|=0.0008`

---

Three-point CDF (Central difference formula)
`f^'(x)=(f(x+h)-f(x-h))/(2h)`

`f^'(1.2)=(f(1.2+0.05)-f(1.2-0.05))/(2*0.05)`

`f^'(1.2)=(f(1.25)-f(1.15))/0.1`

`f^'(1.2)=(0.3153-0.4085)/0.1`

`f^'(1.2)=-0.9317`

Absolute Error:`|"exact value of " f^'(1.2)-(-0.9317)|=|-0.932 +0.9317|=0.0004`

---

Three-point FDF (Forward difference formula) for second derivatives
`f^('')(x)=(f(x)-2f(x+h)+f(x+2h))/(h^2)`

`f^('')(1.2)=(f(1.2)-2f(1.2+0.05)+f(1.2+2*0.05))/((0.05)^2)`

`f^('')(1.2)=(f(1.2)-2f(1.25)+f(1.3))/(0.0025)`

`f^('')(1.2)=(0.3624-2(0.3153)+0.2675)/(0.0025)`

`f^('')(1.2)=-0.3153`

Absolute Error:`|"exact value of " f^('')(1.2)-(-0.3153)|=|-0.3624 +0.3153|=0.0471`

---

Three-point BDF (Backward difference formula) for second derivatives
`f^('')(x)=(f(x-2h)-2f(x-h)+f(x))/(h^2)`

`f^('')(1.2)=(f(1.2-2*0.05)-2f(1.2-0.05)+f(1.2))/((0.05)^2)`

`f^('')(1.2)=(f(1.1)-2f(1.15)+f(1.2))/(0.0025)`

`f^('')(1.2)=(0.4536-2(0.4085)+0.3624)/(0.0025)`

`f^('')(1.2)=-0.4084`

Absolute Error:`|"exact value of " f^('')(1.2)-(-0.4084)|=|-0.3624 +0.4084|=0.046`

---

Three-point CDF (Central difference formula) for second derivatives
`f^('')(x)=(f(x-h)-2f(x)+f(x+h))/(h^2)`

`f^('')(1.2)=(f(1.2-0.05)-2f(1.2)+f(1.2+0.05))/(0.05)^2`

`f^('')(1.2)=(f(1.15)-2f(1.2)+f(1.25))/(0.0025)`

`f^('')(1.2)=(0.4085-2(0.3624)+0.3153)/(0.0025)`

`f^('')(1.2)=-0.3623`

Absolute Error:`|"exact value of " f^('')(1.2)-(-0.3623)|=|-0.3624 +0.3623|=0.0001`

---

---