2. `y=(x+2)^2-9`, find Parity of a function

Solution:
`y=(x+2)^2-9`

Siplyfing vertex form equation `y=(x+2)^2-9`, we get

`y=(x+2)^2-9`

`y=(x^2+4x+4)-9`

`y=x^2+4x-5`

Parity :
Even Function : A function is even if `f(-x)=f(x)` for all `x in R`

Odd Function : A function is odd if `f(-x)=-f(x)` for all `x in R`

`f(-x)=(-x)^2+4(-x)-5`

`f(-x)=x^2-4x-5`

`f(x)!=f(-x)`

`x^2+4x-5` is not an even function

`-f(x)=-(x^2+4x-5)`

`-f(x)=-x^2-4x+5`

`f(x)!=-f(x)`

`x^2+4x-5` is not an odd function

`:. x^2+4x-5` is neither even nor odd function

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