1. `y=(x+2)^2-9`, find axis symmetry of a parabola

Solution:
`y=(x+2)^2-9`

1. Symmetry :
Axis of symmetry is the line that passes through the vertex and the focus
`x=h=-2`

2. Graph :
some extra points to plot the graph
`y=f(x)=(x+2)^2-9`

`f(-6)=(-6+2)^2-9=16-9=7`

`f(-5)=(-5+2)^2-9=9-9=0`

`f(-4)=(-4+2)^2-9=4-9=-5`

`f(-3)=(-3+2)^2-9=1-9=-8`

`f(-2)=(-2+2)^2-9=0-9=-9`

`f(-1)=(-1+2)^2-9=1-9=-8`

`f(0)=(0+2)^2-9=4-9=-5`

`f(1)=(1+2)^2-9=9-9=0`

`f(2)=(2+2)^2-9=16-9=7`

graph

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